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4 years ago

Literal equations 2x-3y=8 solve for y

Mathematics

2 answers:

ludmilkaskok [199]4 years ago

7 0

2x - 3y = 8
- 3y = 8 - 2x
y = ( 8 - 2x ) / -3

or

2x - 3y = 8
2x = 8 + 3y
2x - 8 = 3y
(2x - 8) / 3 = y

vichka [17]4 years ago

4 0

2x-3y = 8

Add 3y on both sides

2x = 8 + 3y

Subtract 8 on both sides

3y = 2x - 8

Divide 3 on both sides

$y= \frac{2}{3}x- \frac{8}{3}$

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The price of a shirt was marked up from $24 to $30What is the percent of increase?

deff fn [24]

Answer:

25% increase

Step-by-step explanation:

First take the new price and subtract the original price

30-24 = 6

Divide by the original price

6/24 = 1/4 = .25

Change to percent form

25%

The price went up so it is an increase

25% increase

8 0

3 years ago

Read 2 more answers

HELP WITH ALL <br> Determine the composite functions of the following set of functions

elixir [45]

QUESTION 1

i) Given $f(x)=5x-2$ and $g(x)=x^2$ .

$(f\circ g)=f(g(x))$

$(f\circ g)=f(x^2)$

We plug in $x^2$ into $f(x)=5x-2$

$(f\circ g)=5x^2-2$

ii) Given $f(x)=5x-2$ and $g(x)=x^2$ .

$(g\circ f)=g(f(x))$

$(g\circ f)=g(5x-2)$

We plug in $5x-2$ into $g(x)=x^2$

$(g\circ f)=(5x-2)^2$

$(g\circ f)=25x^2-10x-10x+4$

$(g\circ f)=25x^2-20x+4$

QUESTION 2

i) Given $g(x)=x^2-4$ and $h(x)=\sqrt{2x+1}$ .

$(h\circ g)=h(g(x))$

$(h\circ g)=h(x^2-4)$

We plug in $x^2-4$ into $h(x)=\sqrt{2x+1}$

$(h\circ g)=\sqrt{2(x^2-4)+1}$

$(h\circ g)=\sqrt{2x^2-8+1}$

$(h\circ g)=\sqrt{2x^2-7}$

ii) Given $g(x)=x^2-4$ and $h(x)=\sqrt{2x+1}$ .

$(g\circ h)=g(h(x))$

$(g\circ h)=g(\sqrt{2x+1})$

We plug in $\sqrt{2x+1$ into $g(x)=x^2-4$

$(g\circ h)=(\sqrt{2x+1})^2-4$

$(g\circ h)=2x+1-4$

$(g\circ h)=2x-3$

QUESTION 3

i) Given $g(x)=x+5$ and $h(x)=\sqrt{x-4}$ .

$(g\circ h)=g(h(x))$

$(g\circ h)=g(\sqrt{x-4})$

We plug in $\sqrt{x-4}$ into $g(x)=x+5$

$(g\circ h)=\sqrt{(x-4)+5}$

ii) Given $g(x)=x+5$ and $h(x)=\sqrt{x-4}$ .

$(g\circ g)=g(g(x))$

$(g\circ g)=g(x+5)$

We plug in $x+5$ into $g(x)=x+5$

$(g\circ g)=(x+5)+5}$

$(g\circ g)=x+10}$

QUESTION 4

The given functions are;

$f(x)=-2x+1$ and $g(x)=-x^2$

$f\circ f=f(f(x))$

$f\circ f=f(-2x+1)$

$f\circ f=-2(-2x+1)+1)$

$f\circ f=4x-2+1)$

$f\circ f=4x-1)$

ii)

$g\circ g=g(g(x))$

$g\circ g=g(-x^2)$

$g\circ g=-(x^2)^2$

$g\circ g=-x^4$

QUESTION 5

$f(x)=5x-2;g(x)=x^2;h(x)=-3x$

$h\circ g\circ f=h\circ (g(f(x))$

$h\circ g\circ f=h\circ (g(5x-2))$

$h\circ g\circ f=h\circ ((5x-2)^2)$

$h\circ g\circ f=h\circ (25x^2-20x+4)$

$h\circ g\circ f=h(25x^2-20x+4)$

$h\circ g\circ f=-3(25x^2-20x+4)$

$h\circ g\circ f=-75x^2+60x-12)$

ii.

$f\circ f\circ g=f\circ (f(g(x))$

$f\circ f\circ g=f\circ (f(x^2)$

$f\circ f\circ g=f\circ (5x^2-2)$

$f\circ f\circ g=f(5x^2-2)$

$f\circ f\circ g=5(5x^2-2)-2$

$f\circ f\circ g=25x^2-10-2$

$f\circ f\circ g=25x^2-12$

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3 years ago

What is the relationship between angle 1 and angle 5

Sauron [17]

Answer:

○ b Corresponding Angles

Step-by-step explanation:

These two angles are a mirror, so they <em>correspond</em>.

I am joyous to assist you anytime.

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4 years ago

220x + 260y < 4,500 solve

Allisa [31]

Answer:

255-13y

x<_________

Step-by-step explanation:

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3 years ago

A driver is 15 feet below the surface of the water 10 seconds after he entered the water and 90 feet below the surface after 40

spin [16.1K]

Answer:

$\frac{-75ft}{30sec}$ or simplified would be $\frac{-2.5ft}{sec}$

Step-by-step explanation:

In order to calculate the rate of change, we must subtract his end position and end time by the starting position and starting time. We are using the -15 feet since it is below the surface area as the starting position and the 10 seconds as the starting time. We make each of these into a fraction and subtract like so...

$\frac{-90ft - (-15ft)}{40sec - 10sec} =$ rate of change

$\frac{-75ft}{30sec} =$ rate of change

$\frac{-2.5ft}{sec}$ = rate of change

Therefore, we can see that the rate of change of the diver is $\frac{-75ft}{30sec}$ or simplified would be $\frac{-2.5ft}{sec}$

6 0

3 years ago