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ankoles [38]
3 years ago
12

What is the domain of this function?

Mathematics
1 answer:
Oxana [17]3 years ago
5 0
Answer:
{x | x > 8}

Explanation:
On the graph, the left end has a dot on x = 0, not an arrow, so the graph does not reach left of x = 0.

On the right end, there is an arrow where x = 8, which means the graph continues past x = 8.
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Need help as fast as possible please I will mark BRAINLIST only for correct answers :) Thank you!
zavuch27 [327]

Answer:

a

Step-by-step explanation:

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2 years ago
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Hii! hopefully you can answer this :)
Gekata [30.6K]

Answer:

1.C

2.A

Step-by-step explanation:

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3 years ago
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In triangle ABC below, sinC=h/a and sinA=h/c. Which of the following combines the two sine ratios into one equation?
LenaWriter [7]

We know:

sin(C)=\frac{h}{a}

and

sin(A)=\frac{h}{c}


These expressions have an h term in common. We can combine them if we can find forms of the expressions in terms of h:

h=a(sin(C))

h=c(sin(A))


Now, because h=h (by the reflexive property), we can write:


a(sin(C))=c(sin(A))


This is our answer, A.

4 0
3 years ago
Need an answer as soon as possible.
Elza [17]
Part A

Answer: The common ratio is -2

-----------------------------------

Explanation: 

To get the common ratio r, we divide any term by the previous one

One example:
r = common ratio
r = (second term)/(first term)
r = (-2)/(1)
r = -2

Another example:
r = common ratio
r = (third term)/(second term)
r = (4)/(-2)
r = -2
and we get the same common ratio every time

Side Note: each term is multiplied by -2 to get the next term

============================================================
Part B

Answer:
The rule for the sequence is 
a(n) = (-2)^(n-1)
where n starts at n = 1

-----------------------------------

Explanation:

Recall that any geometric sequence has the nth term
a(n) = a*(r)^(n-1)
where the 'a' on the right side is the first term and r is the common ratio

The first term given to use is a = 1 and the common ratio found in part A above was r = -2
So,
a(n) = a*(r)^(n-1)
a(n) = 1*(-2)^(n-1)
a(n) = (-2)^(n-1)

============================================================
Part C

Answer: The next three terms are 16, -32, 64

-----------------------------------

Explanation:

We can simply multiply each previous term by -2 to get the next term. Do this three times to generate the next three terms

-8*(-2) = 16
16*(-2) = -32
-32*(-2) = 64

showing that the next three terms are 16, -32, and 64

An alternative is to use the formula found in part B

Plug in n = 5 to find the fifth term
a(n) = (-2)^(n-1)
a(5) = (-2)^(5-1)
a(5) = (-2)^(4)
a(5) = 16 .... which matches with what we got earlier

Then plug in n = 6
a(n) = (-2)^(n-1)
a(6) = (-2)^(6-1)
a(6) = (-2)^(5)
a(6) = -32 .... which matches with what we got earlier

Then plug in n = 7
a(n) = (-2)^(n-1)
a(7) = (-2)^(7-1)
a(7) = (-2)^(6)
a(7) = 64 .... which matches with what we got earlier

while the second method takes a bit more work, its handy for when you want to find terms beyond the given sequence (eg: the 28th term)
6 0
3 years ago
A farmer needs to box 740 apples. A box holds 9 apples. If every box is full except for the last, how many apples are in the las
erma4kov [3.2K]
9 times 82 = 738 740-738=2
6 0
2 years ago
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