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e-lub [12.9K]
3 years ago
10

The poduct of 10 and a number is 3 less than the number

Mathematics
1 answer:
Oxana [17]3 years ago
3 0

Answer:

Step-by-step explanation:

10 x = x - 3     Subtract x from both sides

10x - x = - 3    Combine like terms on the left

9x = - 3           Divide both sides by 9

9x/9 = -3/9

x = - 1/3 or x = - 0.333333

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Divide the following polynomials (a4 + 4b4) ÷ (a2 - 2ab + 2b2)
telo118 [61]
(a^4 + 4b^4) ÷ (a^2 - 2ab + 2b^2)
= [(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)] / (a^2 - 2ab + 2b^2)
= a^2+2ab+2b^2 =The answer

(a + b)^2 = a^2 + 2ab + b^2 => square of sums
(a - b)^2 = a^2 - 2ab + b^2 => square of deference
and of course one of most important ones:
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Best Answer: (a^4 + 4b^4) ÷ (a^2 - 2ab + 2b^2)
= [(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)] / (a^2 - 2ab + 2b^2)
= a^2 + 2ab + 2b^2
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a^4 + 4a^2b^2 + 4b^4 => a^2 + 2ab + b^2 = (a + b)^2, if : a = a^2 , b = 2b^2:
(a^2 + 2b^2)^2 = a^4 + 4a^2b^2 + 4b^4 => We can't add or subtract the value to the expression.
a^4 + 4a^2b^2 + 4b^4 - 4a^2b^2 =>
(a^2 + 2b^2)^2 - 4a^2b^2 =>
(a^2 + 2b^2 - 2ab)(a^2 + 2b^2 + 2ab) =>
(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)

Greetings!


8 0
3 years ago
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Answer:

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Step-by-step explanation:

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