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Crazy boy [7]
3 years ago
15

The 420 lies between what 2 integers?

Mathematics
1 answer:
rewona [7]3 years ago
5 0
It can lie between any number lower than it and any number high than it.
For example, 419 and 421
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The amount of money Chaz earned for walking dogs is given in the table. Can the relationship be described by a constant rate? Ex
mojhsa [17]

Answer:

Yes, the relationship can be described by a constant rate of $18.75 per dog

Step-by-step explanation:

see the attached figure to better understand the problem

Let

x ----> the number of dogs

y ---> the amount of money earned

we have the points

(6,112,50), (8,150), (11,206.25)

step 1

Find the slope with the first and second point

(6,112,50), (8,150)

m=(150-112.50)/(8-6)=18.75

step 2

Find the slope with the first and third point

(6,112,50), (11,206.25)

m=(206.25-112.50)/(11-6)=18.75

Compare the slopes

The slopes are the same

That means, that the three points lies on the same line

therefore

Yes, the relationship can be described by a constant rate of $18.75 per dog

7 0
3 years ago
Graph the line that has a slope of 6 and includes the point (0,4).
faust18 [17]

Answer:

The equation of the line with slope 6 and containing the point (0, 4) will be:

y = 6x+4

The graph of the line y = 6x+4 is attached below.

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given

  • The slope m = 6
  • The point (0, 4)

The y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

The point (0, 4) indicates that:

at x = 0, y = 4

Thus, the y-intercept b = 4

now substituting b = 4 and m = 6 in the slope-intercept form of the line equation

y = mx+b

y = 6x+4

Thus, the equation of the line with slope 6 and containing the point (0, 4) will be:

y = 6x+4

The graph of the line y = 6x+4 is attached below.

3 0
3 years ago
Select all that are measures of angles coterminal with a 145° angle.
Mamont248 [21]
The first 2 and last 2. I just did this assignment
3 0
3 years ago
Read 2 more answers
An airplane travels about 1,500 Km in a straight line between Toronto and Winnipeg. However, the plane must climb to 10,000 m du
Anna007 [38]

Answer:416

Step-by-step explanation: Based on the given problem above, it requires a trigonometric solution. So here it goes:

The climb distance is:200 * Sec [ArcTan [10/200]] = 10√ 401 km

and the decent distance is:300 * Sec [ArcTan [10/300]] = 10√901 km

So add the given results above with 500 km and this will be the additional distance that plane moves through the air.

The answer would be in the unit meters.

((10√401 +10√901−500)∗1000)=416 meters

Hope this is the answer that you are looking for.

7 0
3 years ago
Write a linear function rule for the data in the table.<br><br> x 0 1 2 3 4<br> y 3 1 –1 –3 –5
Dima020 [189]

Answer:

f(x) = –2x + 3

Step-by-step explanation:

7 0
3 years ago
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