Calculate y'. xy^4+x^2y=x+3y

Mathematics

1 answer:

Diano4ka-milaya [45]3 years ago

4 0

Y^4 + 4xy^3 (y') + 2xy + x^2 (y') = 1 + 3 (y')
(y')(4xy^3 + x^2 - 3) = 1 -y^4 -2xy

I'll let you do the next line

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