Question

there are two boxes. in the first box there are 7 cards numbered from 1 tp 7 the second box also contains 7 cards from 1-7 pick one card from each box. find the probability that the sum of the two two cards is at least 12

Answer 1

Answer:

$\frac{6}{49}$

Step-by-step explanation:

GIVEN: There are two boxes. in the first box there are $7$ cards numbered from $1$ to $7$ the second box also contains $7$ cards from $1-7$ pick one card from each box.

TO FIND: probability that the sum of the two two cards is at least $12$.

SOLUTION:

sample case such that sum of cards is $12$ : $(5,7),(7,5),(6,6)$

sample case such that sum of cards is $13$ : $(7,6),(6,7)$

sample case such that sum of cards is $14$ : $(7,7)$

Total sample case such that sum is atleast $12$ $=6$

Total sample cases$=49$

probability that the sum of the two two cards is at least $12$$=\frac{\text{sample case in which sum is atleast 12}}{\text{total sample cases}}$

$=\frac{6}{49}$

probability that the sum of the two two cards is at least $12$ is $\frac{6}{49}$