The perimeter = sum of all sides
= 120 + 80 + 50
= 250
So 250 - 3
247
Left space for gate
Now cost of fencing = Rs 20/per meter
= 247 × 20
= Rs 4,940
Now the area of the triangular park can be found using heron's formula
S = (a+b+c)/2
S = (120+80+50)/2
S = 250/2
S = 125
Now
Herons formula = √s(s-a)(s-b)(s-c)
√125(125-120)(125-80)(120-50)
√125(5)(45)(70)
√5×5×5×5×5×3×3×5×14
After Making pairs
5×5×5×3√14
375√14
Therefore 375√14m is the area of the triangular park
Must click thanks and mark brainliest
Answer:
67
Step-by-step explanation:
its not a 90!!! tilt your screen.
Answer
Arc EF = 52°
Arc HD = 142°
Angle HGF = 128°
Explanation
To solve for the unknown angles, we need to first solve for x
To do that, we need to first note that the sum of angles on a straight line is 180°
So,
Angle HCG + Angle HCD = 180° (Sum of angles on a straight line)
Angle HCG = 2x
Angle HCD = 6x + 28°
Angle HCG + Angle HCD = 180°
2x + 6x + 28° = 180°
8x + 28° = 180°
8x = 180° - 28°
8x = 152°
Divide both sides by 8
(8x/8) = (152°/8)
x = 19°
Angle HCG = 2x = 2 (19°) = 38°
Angle HCD = 6x + 28° = 6(19°) + 28° = 142°
So, we can solve for the rest now
Arc EF = Angle ECF
= 90° - Angle ECD
Angle ECD = Angle HCG = 38° (Vertically opposite angles are equal)
Arc EF = Angle ECF
= 90° - Angle ECD
= 90° - 38°
= 52°
Arc HD = Angle HCD = 142°
Angle HGF = Angle HCG + Angle GCF = 38° + 90° = 128°
Hope this Helps!!!
Answer:
c. 0 and 7
Step-by-step explanation:
