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Natasha2012 [34]
2 years ago
5

Evaluate 4(2a – b) when a = –1 and b = 5.

Mathematics
2 answers:
grin007 [14]2 years ago
3 0

Hey There!

<h2><u>Question:-</u></h2>

\sf \longmapsto \: 4(2a - b)

<em>This is a algebraic expression. The values of a and b are given. The values are as follows :-</em>

a = -1

And,

b = +5 .

<h2><u>Solution</u><u>:</u><u>-</u></h2>

\sf \longmapsto4(2a  -  b)

<em>Note that </em><u>a </u><em>is multiplied with 2 that is :-</em>

\sf \longmapsto4(2 \times a \:  - b)

<u>Now, Insert the values that is a = -1 and b = 5 :-</u>

\sf \longmapsto4(2   \times  -  1 - 5)

Here,we need to follow BODMAS Rule.

B = Brackets

O = Orders

D = Division

M = Multiplication

A = Addition

S = Subtraction

<em>We need to solve the bracket's </em><em>calculations</em><em> </em><em>first</em><em> </em><em>as </em><em>it </em><em>is </em><em>the</em><em> </em><em>rule.</em>

<u>So, Firstly Multiply (2 × -1)</u><u> </u><u>:</u><u>-</u>

\sf \longmapsto4( - 2 - 5)

Note that, (-) × (-) equals to (+).

So, it will be 5+2,But as 5 is bigger number than 2, 5 contains a minus sign.So the result will be -7.

\sf \longmapsto4(  5+ 2)

<em>On Simplification:-</em>

\sf \longmapsto4( - 7)

\sf \longmapsto4  \times (- 7)

\sf \longmapsto \:  - 28

______________________________________

<em>Henceforth the solution of the algebraic expression is :-</em>

\bf \:- 28

Option B is correct!

______________________________________

I hope this helps!

Please let me know if you have any questions.

~MisterBrian

VikaD [51]2 years ago
3 0
4(2(-1)-5)
4(-2-5)
4(-7)
=-28 (B)
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