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2 years ago

Identify the greatest rommon factor: 3x²y - 6xy2

Mathematics

2 answers:

Over [174]2 years ago

6 0

The answer is : 3xy(x-2y)

Mrac [35]2 years ago

3 0

Answer:

If you're looking to simplify, the greatest common factor should be 3xy.

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PLEASE HELP ASAP <br> FIND THE MEASUREMENT QP<br> 20 POINTS

ahrayia [7]

Answer:

a^2+b^2=c^2

a^2+b^2=8^2

a^2+b^2=64

32+32=64

5.66^2+5.66^2=8^2

Step-by-step explanation:

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5 0

2 years ago

Which triangle is a 30° -60° -90° triangle?

Fittoniya [83]

Answer:

Acute isosceles triangle

Step-by-step explanation:

because an acute angle is more than 45 but less then 90.

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2 years ago

At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a

morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = $\dfrac{15}{120}=0.125$

As we know the poisson process, we get that

$P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda$

So, for exactly one car would be

P(n=1) is given by

$=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599$

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

$0.2599\times 18=4.6798$

We will find the traffic flow q such that

$P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr$