Complete question:
The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at
Answer:
27,800
Step-by-step explanation:
We need to obtain the initial population(P0) and constant value (k)
Population function : p(t) = P0e^kt
At t = 0, population = 19,000
19,000 = P0e^(k*0)
19,000 = P0 * e^0
19000 = P0 * 1
19000 = P0
Hence, initial population = 19,000
At t = 3; population = 23,000
23,000 = 19000e^(k*3)
23000 = 19000 * e^3k
e^3k = 23000/ 19000
e^3k = 1.2105263
Take the ln
3k = ln(1.2105263)
k = 0.1910552 / 3
k = 0.0636850
At t = 6
p(t) = P0e^kt
p(6) = 19000 * e^(0.0636850 * 6)
P(6) = 19000 * e^0.3821104
P(6) = 19000 * 1.4653739
P(6) = 27842.104
27,800 ( nearest whole number)
3 marbles as there is only one green and there is three other blue marbles left and that answer is incorrect
Answer:
Measure of angle A = 55°.
Step-by-step explanation:
From the picture attached,
2 = 2
Corresponding sides of the given triangles ΔACB and ΔNLM are proportional.
Therefore, ΔACB ~ ΔNLM.
m∠A = 180° - (90° + 35°) [By triangle sum theorem]
= 180° - 125°
= 55°
Measure of angle A is 55°.
These are how the graphs will look, they are color coded so have a look at the equations first.
