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SCORPION-xisa [38]
3 years ago
14

Find the circumference

Mathematics
2 answers:
PIT_PIT [208]3 years ago
6 0

Answer:

90 units

Step-by-step explanation:

circumference C = 2 \pir

taking \pi as 3.

C = 2 × 3 × 15

(15 is the radius of the circle)

C = 90 units

valkas [14]3 years ago
5 0

Answer:

90

Step-by-step explanation:

The Answer will be 90 because Pie is being replaced with 3, so it would be like 2(3)(15) which equals to 90.

But If Pie remains pie the equation would look like (2)(3.14)(15) which would turn out to be 94.2

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katovenus [111]
There are four scores.
So to find the mean or average, you add all four scores and then divide by 4.

I get 119, then divide by 4, to get 29 and 3/4 or 29.75.
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Solve the exponential equation. Use a calculator to obtain a decimal approximation, correct to two decimal places, for the solut
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3 years ago
What is the missing side length in this right triangle?
Harrizon [31]

Answer:

A. 15

Step-by-step explanation:

Ooh, look! This triangle is a Pythagorean triple! Without even needing to use a formula, I can tell that you are correct and the answer is A. 15.

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5 0
3 years ago
Read 2 more answers
With double-digit annual percentage increases in the cost of health insurance, more and more workers are likely to lack health i
Dahasolnce [82]

Answer:

1.  χ² = <u>  15.3902 </u>

2. The p value is :_____.a. less than .005

3.  Conclusion

a. health insurance coverage is not independent of the size of the company

4. The percentages of employees

Small %=   33/50= 0.66

Medium %= 68/75 = 0.91

Large %= 88/100= 0.88

Step-by-step explanation:

1) We set up our null and alternative hypothesis as

H0: the employee health insurance coverage is independent of the size of the company

against the claim

Ha: the employee health insurance coverage is not independent of the size of the company

2) the significance level alpha is set at 0.05

3) the test statistic under H0 is

χ²= ∑ (O - E)²/ E where O is the observed and E is the expected frequency

which has an approximate chi square distribution with ( 3-1) (2-1)=  2 d.f

4) Computations:

Under H0 , the observed frequencies are :

Observed       Expected E        (O-E)         (O-E)²             (O-E)²/E

33                   42                      -9               81                    1.928  

68                  63                         5              25                  0.3968

88                  84                         4               16                  0.1904

17                    8                           9              81                  10.125

7                     12                          -5             21                    1.75

<u>12                    16                         -4              16                     1              </u>

<u>                                                                                           15.3902    </u>

Expected Values are calculated using the formula :

Row Total * Column Total / sample size

E1= (33+17) (33+ 68+88)/ 50+75+100= 42

E4= (33+17) (17+ 7+ 12)/ 50+75+100=8

E2= (68+7) (33+ 68+88)/ 50+75+100= 63

E5= (68+7)  (17+ 7+ 12)/ 50+75+100= 12

E3= (88+12) (33+ 68+88)/ 50+75+100= 84

E6= (88+12)  (17+ 7+ 12)/ 50+75+100= 16

5) The critical region is χ² ≥ χ² (0.05)2 = 5.99

6) Conclusion:

The calculated χ² = <u>  15.3902    </u>falls in the critical region χ² ≥  5.99  so we reject the null hypothesis that the employee health insurance coverage is NOT independent of the size of the company.

2. The p value is :_____.

a. less than .005

The p-value is .000385.

3.  Conclusion

a. health insurance coverage is not independent of the size of the company

4. The percentages of employees

Small %=   33/50= 0.66

Medium %= 68/75 = 0.91

Large %= 88/100= 0.88

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2 years ago
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A.


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