The answer to your problem is 2
$1350-$750=$600
2010-2000=10 years
600/10=$60 increase per year
a) since elliot started with $750 in 2000 and he started working in 2000 that would be his initial fee and every year he increased his fee by $60.
b) y=60x+750
1/5 is .2
.1^2 is .01
.02 is .02
So the furthest left would be the smallest number, which in this case is 0.1^2
Add all numbers together, then divide by the number of numbers there are. in this case divide by 6
