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Serjik [45]
3 years ago
14

The first 100 customers to purchase the system the store gives me a 20% discou t off tge regular cost if i pay 500 for the gamin

g dystem at the discou ted price what is tge regular cost of tge gaming system
Mathematics
1 answer:
IrinaVladis [17]3 years ago
7 0

Answer:

2,500

Step-by-step explanation:

The computation of the cost of the regular cost of the gaming system is shown below:

As in the question it is mentioned that for first 100 customers the 20% discount rate is applicabke

Now if a person pays 500 at the discount price i.e. after discounted percentage

So, the regular cost would e

= 500 × 1 ÷ 0.20

= 2,500

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Step-by-step explanation:

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An airplane left Atlanta with 20 empty seats. If the airplane was 75% full, what was the total number of seats on the airplane?
jek_recluse [69]
Answer is <span>C. 80

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8 0
3 years ago
Which property can you use to simplify (4+10)+(-10)
Anarel [89]

Answer:

Associative property of addition

Step-by-step explanation:

(4+10)+(-10)

We want to change the parentheses to

4 + ( 10 + -10)

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( a+b) + c = a+ ( b+c)

6 0
3 years ago
Read 2 more answers
Match the following rational expressions to their rewritten forms.
Nookie1986 [14]

Answer:

Answer image is attached.

Step-by-step explanation:

Given rational expressions:

1.\ \dfrac{x^2+x+4}{x-2}\\2.\ \dfrac{x^2-x+4}{x-2}\\3.\ \dfrac{x^2-4x+10}{x-2}\\4.\ \dfrac{x^2-5x+16}{x-2}

And the rewritten forms:

(x-2)+\dfrac{6}{x-2}\\(x+3)+\dfrac{10}{x-2}\\(x+1)+\dfrac{6}{x-2}\\(x-3)+\dfrac{10}{x-2}

We have to match the rewritten terms with the given expressions.

Let us consider the rewritten terms and let us solve them one by one by taking LCM.

(x-2)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x-2)^{2}+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+4+6 }{x-2}\\\Rightarrow \dfrac{x^2-4x+10}{x-2}

So, correct option is 3.

(x+3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x+3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{(x^2+3x-2x-6)+10}{x-2}\\\Rightarrow \dfrac{x^2+x+4}{x-2}

So, correct option is 1.

(x+1)+\dfrac{6}{x-2}\\\Rightarrow \dfrac{(x+1)(x-2)+6}{x-2}\\\Rightarrow \dfrac{x^{2} +x-2x-2+6}{x-2}\\\Rightarrow \dfrac{x^{2} -x+4}{x-2}

So, correct option is 2.

(x-3)+\dfrac{10}{x-2}\\\Rightarrow \dfrac{(x-3)(x-2)+10}{x-2}\\\Rightarrow \dfrac{x^2-3x-2x+6+10}{x-2}\\\Rightarrow \dfrac{x^2-5x+16}{x-2}

So, correct option is 4.

The answer is also attached in the answer area.

7 0
3 years ago
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