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2 years ago

There exists a similarity transformation that maps AABC to AA'B'C'. The measure

Mathematics

2 answers:

Artist 52 [7]2 years ago

6 0

Answer:

∠C' = 66°

Step-by-step explanation:

∠A' + ∠B' + ∠C' = 180

68 + 46 + ∠C' = 180

114 + ∠C' = 180

∠C' = 66°

Dmitry [639]2 years ago

4 0

Answer:

∠C' = 66°

Step-by-step explanation:

Because triangles ABC and A'B'C' are similar, their angles are still the same; only their side lengths are different, though still proportionate.

Hence, ∠A = ∠A', ∠B = ∠B', and ∠C = ∠C'.

Here, we're given that ∠A = 68, which means ∠A' = 68; we also know that ∠B = 46, so ∠B' = 46.

We want to find C', so remember that all angles in a triangle sum to 180:

∠A' + ∠B' + ∠C' = 180

68 + 46 + ∠C' = 180

114 + ∠C' = 180

∠C' = 66°

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There are 25 prime numbers between 1 and 100. There are 46 prime numbers between 1 and 200. Which situation is more likely? Expl

Alekssandra [29.7K]

Answer:

One.

Step-by-step explanation:

There is a 25% chance of situation one happening.

$\frac{prime}{total} =\frac{25}{100} = 0.25=25$ %

There is a 23% chance of situation two happening.

$\frac{prime}{total} =\frac{46}{200}=0.23=23$ %

Since the chance is two percent bigger from situation one, situation one should be the one that is more likely to happen.

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3 years ago

1. (2,7); m=-4 What’s the answer?

Nataly_w [17]

Answer:

4x + y = 15 or y = -4x + 15

Step-by-step explanation:

7 = 2[-4] + b

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15 = b

$y = -4x + 15$

If you want it in Standard Form:

y = -4x + 15

+4x +4x

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4x + y = 15 >> Line in Standard Form

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3 years ago

Exercise 7.3.5 The following is a Markov (migration) matrix for three locations        1 5 1 5 2 5 2 5 2 5 1 5 2 5 2 5 2

fredd [130]

Answer:

Both get the same results that is,

$\left[\begin{array}{ccc}140\\160\\200\end{array}\right]$

Step-by-step explanation:

Given :

$\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]$

and initial population,

$\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]$

a) - After two times, we will find in each position.

$P_2=[P].[M]^2=[P].[M].[M]$

$M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]$

$=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]$

$\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]$

b) - With in migration process, 500 people are numbered. There will be after a long time,

$After\;inifinite\;period=[M]^n.[P]$

$Then,\;we\;get\;the\;same\;result\;if\;we\;measure [M]^n=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]$

$=\left[\begin{array}{ccc}140\\160\\200\end{array}\right]$

4 0

3 years ago

What is this simplified? Please help

Naya [18.7K]

Answer:

The end result is -1/(x + 1)

Step-by-step explanation:

In order to find the answer to this, we first need to factor the denominator. Since it is a quadratic, we try to find number that multiply to the last term (8) and add to the middle term (9). In this case, the numbers 8 and 1 would work. This allows us to use those numbers in parenthesis along with x as a fully factored form.

x^2 + 9x + 8 = (x + 1)(x + 8)

Now that we have this factored we can take the original equation and factor a -1 out of the top.

(-1)(x + 8)/(x + 1)(x + 8)

Since there is an (x + 8) on the top and bottom, we can cancel those.

-1/(x + 1)

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3 years ago

The recursive formula for a geometric sequence is: a = 4 an=an-1×3 What is the 3rd term of this sequence?

timama [110]

Answer:

Step-by-step explanation:

a1 = 4

an=an-1 *3

a2 = a1 *3 = 4*3 = 12

a3 = a2*3 = 12*3 = 36

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3 years ago