Question

There exists a similarity transformation that maps AABC to AA'B'C'. The measure

Answer 1

Answer:

∠C' = 66°

Step-by-step explanation:

∠A' + ∠B' + ∠C' = 180

68 + 46 + ∠C' = 180

114 + ∠C' = 180

∠C' = 66°

Answer 2

Answer:

∠C' = 66°

Step-by-step explanation:

Because triangles ABC and A'B'C' are similar, their angles are still the same; only their side lengths are different, though still proportionate.

Hence, ∠A = ∠A', ∠B = ∠B', and ∠C = ∠C'.

Here, we're given that ∠A = 68, which means ∠A' = 68; we also know that ∠B = 46, so ∠B' = 46.

We want to find C', so remember that all angles in a triangle sum to 180:

∠A' + ∠B' + ∠C' = 180

68 + 46 + ∠C' = 180

114 + ∠C' = 180

∠C' = 66°