Answer:
Maximum width of image that can be viewed clearly on the cylindrical screen is 10 ft
Step-by-step explanation:
Here we have
Circumference of screen = 2πr = 120 ft
Angle that can be viewed horizontally either side of focus = 15°
Total angle view = 30°
Size of image that can be viewed = Object within 30° of focus
Maximum width of image that can be viewed clearly = Perimeter of 30° arc section of cylinder
Maximum width of image that can be viewed clearly = 30/360×120 ft = 10 ft.
Maximum width of image that can be viewed clearly on the cylindrical screen = 10 ft.
Answer:
B
Step-by-step explanation:
P= 16 over 3 this is the straight forward answer
You can use Euler's Polyherdron Formula as seen here;
https://plus.maths.org/content/eulers-polyhedron-formula
The number of vertices minus the number of edges plus the number of Faces will equal 2.
V - E + F = 2
V - 36 + 25 = 2
V = 13
Volume is l * w * h
Length * width * height
to find the volume we would just plug in the values for the length width and the height.
4 * 16 * 20
64 *20 = 1280.
The volume of the box is 1280 cubic units.
