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3 years ago

Use the set of clues in the equations below to find the value of each variable .

1 answer:

soldier1979 [14.2K]3 years ago

4 0

There are many ways to solve this problem. All you have to do is simple algebraic manipulation. Solve for b and h with the two simpler equations:
2b = 12; divide 2 on both sides to get b = 6
h - x = 2; add x to both sides to get h = (2 + x)

Plug this stuff into the first equation to solve for x. Once we solve for x, we can plug that x value into the equation for h. Because you can see we didn’t get an actual numerical value for h. So:
x + (2+x) + 6 = 14
Subtract 6 from both sides and distribute that plus sign to get rid of the parenthesis. Then combine the like terms to get:
2x + 2 = 8
Subtract 2 from both sides and divide by 2 to get x = 3

Finally plug it into the equation for h:
h = 2+3 = 5

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What’s the correct answer for this ?<br> The traffic light is approximately _____ feet tall

wlad13 [49]

Answer:

Height = 21.78 ft

Step-by-step explanation:

Tan θ = opposite / Adjacent

tan 40 = opposite / 20

where opposite is the part of the traffic light

0.839 × 20 = opposite

opposite = 16.78 ft

Now the total height of traffic light = 16.78 ft +5 ft

Total Height = 21.78 ft

8 0

3 years ago

Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,

MrRissso [65]

Answer:

$4.82\cdot 10^{-4}$

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

$p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769$

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

$n-1=51$

Therefore, the probability of drawing a three at the 2nd draw is

$p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784$

Then, at the third draw, the previous 2 cards are not replaced, so there are now

$n-2=50$

cards in the deck. So, the probability of drawing a jack is

$p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08$

Therefore, the total probability of drawing an ace, a three and then a jack is:

$p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}$

4 0

3 years ago

Help pls its just math :( <br><br>Ik it sucks I hate math too, pls help tho

Umnica [9.8K]

Answer:

x = - 1

Step-by-step explanation:

Given

- 4(3x - 7) = 40 ( divide both sides by - 4 )

3x - 7 = - 10 ( add 7 to both sides )

3x = - 3 ( divide both sides by 3 )

x = - 1

6 0

3 years ago

Read 2 more answers

Solve this system of equations without graphing and show your reasoning

Drupady [299]

Answer:

x = 1/5

y = 6

Step-by-step explanation:

System:

{5x + y = 7

{20x + 2 = y

First equation:

5x + y = 7 -> y = -5x + 7

Plug into second equation:

20x + 2 = -5x + 7

Subtract 2 from both sides:

20x = -5x + 5

Add 5x to both sides:

25x = 5

Divde both sides by 25:

x = 5/25 -> 1/5

~~~~~~~~~~~~~~~~~~~~~~~~~~~`

Come back to the first equation:

5x + y = 7

Plus in our x:

5(1/5) + y = 7

Multiply:

1 + y = 7

Subtract 1 from both sides:

y = 6

Hope this helps, have a nice day! :D

7 0

2 years ago

Draw a rectangle that shows 2 equal parts

slava [35]

Just Half it down the middle.

3 0

3 years ago