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2 years ago

How do you factor the inequalities with a number greater than 1 in front of x^2?

Mathematics

1 answer:

Pavlova-9 [17]2 years ago

3 0

Lets simplify this

2x^2 + 2x - 10 _< 2

4x^2 - 10 _< 2

4x^2 _< -8

x^2 _< -2

x _<1.41
on the graph plot a line, then a filled in cirlce at 1.41

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Which expression is equivalent to 3(2x−4)+4x−2

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I hope this helps you

3.2x-3.4+4x-2

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3 years ago

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3x - 6 + 4 = -20

V125BC [204]

Answer:

I'm not sure what all that extra stuff is supposed to mean, but the answer to the top question is: x = -6

Step-by-step explanation:

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2 years ago

In triangle ABC, a = 4, b = 6, and cos C = − 1/4. What is the length of side c?

shusha [124]

The length of side c would be 8.

Step-by-step explanation:

Given that,

a = 4

b = 6

cosC = -1/4

If we are given two sides and angle, the law of Cosines can be used to find the third side:

$c^{2} = a^{2} + b^{2} - 2ab (cos(c))$

By inserting the values in the formula, we get

$c^{2} = 4^{2} + 6^{2} - 2.4.6 (-\frac{1}{4} )$

$c^{2} = 16 + 36 + 12$

$c^{2} = 64$

$\sqrt{c^{2} } = \sqrt{64}$

c = 8.

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7 0

3 years ago

Help me please thank you

Snezhnost [94]

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3 years ago

The sum of three numbers is 120 the first number is five less than the second the third number is three times the second what ar

VladimirAG [237]

Answer:

1st number: 20

2nd number: 25

3rd number: 75

Step-by-step explanation:

x + y + z = 120

x = y - 5

z = 3y

plug that in!

(y-5) + y + (3y) = 120

remove the parenthesis (I used them to show you what I was replacing), and add like terms.

5y - 5 = 120

move -5 to the other side

5y = 120 + 5

5y = 125

divide both sides by 5

y = 25

now that you have one number, use the equations from before to solve for the rest!

x = (25) - 5

z = 3(25)

_____________________________________________________

x = 20

y = 25

z = 75

4 0

2 years ago

How do you factor the inequalities with a number greater than 1 in front of x^2?​

How do you factor the inequalities with a number greater than 1 in front of x^2?