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Umnica [9.8K]
2 years ago
7

Can someone explain to me how to do this? i’m so confused

Mathematics
2 answers:
Mrrafil [7]2 years ago
5 0
Proportion box
3 over 1 is equal to m over 5
So it’s 1m= 15
And then you divide so it’s 1/m=15/1
And it equals to 15
aniked [119]2 years ago
3 0
I think it’s going to be 7! Because since the other triangle is 1 and 3 it’s just 2 more so I just added to more to 5 getting me 7!! I think lol
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a cell phone company plans to market a new smartphone. they have already sold 612 units durning the first week of the campaign.
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The first term is 612.

The common ratio is 1.08 and

The recursive rule is a_{n} = a^{n-1} \times r

<u>Step-by-step explanation:</u>

the question to the problem is to write the values of the first term, common ratio, and expression for the recursive rule.

<u>The first term :</u>

In geometric sequence, the first term is given as a_{1}.

⇒ a_{1} = 612

Now, the geometric sequence follows as 612, 661, ........

<u>The common ratio (r) :</u>

It is the ratio between two consecutive numbers in the sequence.

Therefore, to determine the common ratio, you just divide the number from the number preceding it in the sequence.

⇒ r = 661 divided by 612

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<u>To find the recursive rule :</u>

A geometric series is of the form  a,ar,ar2,ar3,ar4,ar5........

Here, first term a_{1} = a and other terms are obtained by multiplying by r.

  • Observe that each term is r times the previous term.
  • Hence to get nth term we multiply (n−1)th term by r .

The recursive rule is of the form a_{n} = a^{n-1} \times r

This is called recursive formula for geometric sequence.

We know that r = 1.08 and a_{1} = 612.

To find the second term a_{2}, use the recursive rule a_{n} = a^{n-1} \times r

⇒ a_{2} = a^{2-1}\times r

⇒ a_{2} = a^{1}\times r

⇒ a_{2} = 612\times 1.08

⇒ a_{2} = 661

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