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3 years ago

What are all the power of threes through 1000

1 answer:

algol133 years ago

6 0

1000= 10^3 -- ten to the third power

assuming you mean whole numbers,

graba calculator, figure out what
1^3, 2^3 3^3 ... 9^3 are
or
1x1x1
2x2x2
3x3x3
...
9x9x9

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Every day 10% of the liquid present in the morning in Kyle's open container will evaporate. At the end of three days, what perce

lozanna [386]

At the end of three days, $72.9$ % of the original amount of liquid remains in Kyle's container .

Step-by-step explanation:

Here we have , Every day 10% of the liquid present in the morning in Kyle's open container will evaporate. At the end of three days, We need to find what percent of the original amount of liquid remains in Kyle's container . Let's find out:

Let's suppose initially we have 100% of liquid present so ,

At day 1:

10% of the liquid present(100%) in the morning in Kyle's open container will evaporate , So left is :

⇒ $100- \frac{100(10)}{100}$

⇒ $100-10$

⇒ $90$ %

At day 2:

10% of the liquid present(90%) in the morning in Kyle's open container will evaporate , So left is :

⇒ $90- \frac{90(10)}{100}$

⇒ $90-9$

⇒ $81$ %

At day 3:

10% of the liquid present(81%) in the morning in Kyle's open container will evaporate , So left is :

⇒ $81- \frac{81(10)}{100}$

⇒ $81-8.1$

⇒ $72.9$ %

Therefore , At the end of three days, $72.9$ % of the original amount of liquid remains in Kyle's container .

8 0

3 years ago

The midpoint of CD is M=(1, 2). One endpoint is C = (6, -2).

Zina [86]

Answer: Endpoint = (-4,6)

Step-by-step explanation:

To find any endpoint use the formula $\frac{x_1+x_2}{2} = Xmp$ $\frac{y_1+y_2}{2} =Ymp$

$\frac{6+x_2}{2} = 1$ $\frac{-2+y_2}{2} =2$

multiply each by 2 to simplify

$\frac{6+x_2}{2*2} = 1*2 = {6+x_2}= 2$ $\frac{-2+y_2}{2*2} =2*2 = -2+y_2=4$ take the equations and simplify

6+ $x_{2}$ = 2 -2+ $y_{2}$ = 4 =

-6 -6 +2 +2

$x_{2}$ = -4 $y_{2}$ = 6

To check use the Midpoint formula

$\frac{-4+6}{2} , \frac{6-2}{2} = \frac{2}{2} , \frac{4}{2} = (1,2)$

8 0

3 years ago

Solve for: <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%20%2B%205x%20%3D%201" id="TexFormula1" title="x^{2} + 5x = 1

mixer [17]

$x^2+5x-1=0\\x^2+5x+(\frac{5}{2})^2-(\frac{5}{2})^2-1=0\\(x+\frac{5}{2})^2-\frac{25}{4}-\frac{4}{4}=0\\(x+\frac{5}{2})^2-\frac{29}{4}=0\\(x+\frac{5}{2})^2=\frac{29}{4}\\x+\frac{5}{2}=\sqrt{\frac{29}{4}} , x+\frac{5}{2}=-\sqrt{\frac{29}{4}}\\x=\frac{\sqrt{29} }{2} - \frac{5}{2} , x=-\frac{\sqrt{29} }{2} - \frac{5}{2} \\x=\frac{\sqrt{29}-5 }{2} , x=-\frac{\sqrt{29} -5}{2}$

4 0

3 years ago

A rectangle has a length of the fifth root of 16 inches and a width of 2 to the 1 over 5 power inches. Find the area of the rect

gayaneshka [121]

Hello,

It 's difficult to translate that in french.

l=16 ^(1/5)
w=2^(1/5)
Area=32^(1/5)=(2^5)^(1/5)=2 (in²)

7 0

3 years ago

Read 2 more answers

Solve: |x -0.5| < 12

never [62]

Your answer should be -11.5

6 0

3 years ago