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Alexxandr [17]
3 years ago
14

How to calculate angle BCE?

Mathematics
1 answer:
Olenka [21]3 years ago
5 0

Answer:

75.3 degrees ( to nearest tenth).

Step-by-step explanation:

If we take a section  through the plane BCHE we get a rectangle.

BC = 2 cm and BE  = √(7^2 + 3^2). ( By the pythagoras theorem).

tan < BCE = √(7^2 + 3^2) / 2.

So the m < BCE = 75.3 degrees.

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7 0
3 years ago
Kevin and Randy Muise have a jar containing 92 coins, all of which are either quarters or nickels. The total value of the coins
Artemon [7]
<span>Let n = the number of nickles
Let q = the number of quarters
Then for your problem we have
(1) n + q = 43 and
(2) 5*n + 25*q = 100*6.95 (always work in cents to avoid decimal numbers) or
(3) 5*n + 25*q = 695
Now substitute n of (1) into (3) and get
(4) 5*(43 - q) + 25*q = 695 or
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(6) 20*q = 695 - 215 or

(7) 20*q = 480 or
(8) q = 24
Then using (1) we get
(9) n + 24 = 43 or
(10) n = 19
Let's check these values.
Is (.05*19 + .25*24 = 6.95)?
Is (.95 + 6.00 = 6.95)?
Is (6.95 = 6.95)? Yes
Answer: Kevin and Randy have 19 nickles and 24 quarters in the jar.</span>
7 0
3 years ago
In the figure below, EH GJ and FI intersects EH at G as shown below.
Pachacha [2.7K]

Answer:

D. 15°

Step-by-step explanation:

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since JGH is 90° we can say JGI is 90 - 75 = 15°

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3 years ago
(4x3y3)3<br>me pueden ayudar​
Dominik [7]

Answer:

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Step-by-step explanation:

( 4x3y3 ) 3

= 4x ⋅ 3 ⋅ 3y ⋅ 3 ⋅ 3 ⋅ 3

= 12x9y9

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3 years ago
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