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storchak [24]
3 years ago
13

Writte three numbers greater than 20 that has a 9 as a factor

Mathematics
1 answer:
mestny [16]3 years ago
7 0
27, 36, 45

Hope it helps ^^
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The airplane in the scale drawing has a wingspan of a feet and a tailspan of b feet. if the tailspan in the drawing is 2 inches,
Elena L [17]

30 feet is correct. Since a = 3b, the wingspan is 6 inches in the drawing, so it is 6x5 = 30 feet on the plane.


7 0
3 years ago
Read 2 more answers
A quadrilateral has angles that measure 74°, 93°, and 117°.
Tamiku [17]
We know the sum of all the angles in a quadilateral is equal to 360. so,
it would be: 360 - (74+93+117)

 = 360 - 284
 = 76 degrees

So, Your final answer is 76 degrees.

Hope this helps!
4 0
3 years ago
Insurance companies are interested in knowing the population percent of drivers who always buckle up before riding in a car. Whe
kherson [118]

Answer:

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}  

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)

We don't have a prior estimation for the proportion \hat p so we can use 0.5 as an approximation for this case  

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

5 0
3 years ago
A bag contains 3 red marbles 4 blue marbles and 7 Green marbles if two marbles are drawn out of the bag what is the probability
mr_godi [17]

Answer:

0.368

Step-by-step explanation:

Number of red marbles= 3

Number of blue marbles= 4

Number of green marbles= 7

Total number of marbles= 3+4+7= 14

Let the first ball is taken out to be red

P(R)=\frac{3}{14}

than again a second ball is drawn, number of balls left= 14-1=13

Number of red= 2

P(R)=\frac{2}{13}

Total probability=\frac{3}{14}+\frac{2}{13}

Total probability= 0.368

Hence, the correct answer is 0.368

3 0
3 years ago
Did I do these two correctly?
natka813 [3]
Yes you did the equation on this page correctly.
7 0
3 years ago
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