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wlad13 [49]
3 years ago
8

Five less than one fourth of x is y written out

Mathematics
1 answer:
zalisa [80]3 years ago
7 0
1/4x - 5= y
---------------
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Determined the quadrant for an angle with the following characteristics: cotθ>0 and cscθ>0.
oee [108]
\csc\theta=\dfrac1{\sin\theta}>0\implies\sin\theta>0

This happens whenever the terminal point of \theta lies in either the first or second quadrants.

Meanwhile,

\cot\theta=\dfrac1{\tan\theta}=\dfrac{\cos\theta}{\sin\theta}>0\implies\cos\theta>0

since you already know sine is positive. Cosine is positive when the angle lies in the first or fourth quadrant.

Sine and cosine are both positive only when \theta is the first quadrant, which means this angle's terminal point lies in the first quadrant (A).
6 0
3 years ago
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Please help me with my math please.?
Lady_Fox [76]

Answer:

x = 6, y = 0, m = -1
y = mx + b
0 = -1(6) + b
0 = -6 + b
6 = b
y = -1x + (6)

Step-by-step explanation:

^^^
See answer, pretty simple.

4 0
2 years ago
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PLEASE HELP ASAP!!!!! WILL GIVE BRAINLEST TO CORRECT ANSWER
marysya [2.9K]
It is B 80. Because it is 40 x 2 = 80. Hope thishelped
5 0
3 years ago
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You randomly select 2 marbles from a mug containing 5 blue marbles, 4 red marbles, and 3 white marbles. How many times greater i
qwelly [4]

Answer:

2/17

Step-by-step explanation:

Add all the marbles and add the 2 in front because 2 is what you are taking, and 17 is the total of marbles.

5 0
3 years ago
sophie was 28 years old when daughter Nichole was born. In how many years will Sophie be two years less than still times Nichole
Kamila [148]
It will take 6 years for that to happen. 

You can find this by setting Nichole's age as x and Sophie's age as x + 28 since she will always be 28 years older. 

Now we are looking for a time that Sophie's age is equal to 2 less than 6 times Nichole's age. So we can set up the below equation. 

6(x) - 2 = x + 28
6x - 2 = x + 28
5x - 2 = 28
5x = 30
x = 6

This let's us know that it needs to be when Nichole is 6, which is 6 years in the future. 
6 0
3 years ago
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