47 multiplied by 25

An individual can win a prize by drawing the highest numbered card out of five cards. After each draw, the card is replaced and

Mashutka [201]

Answer:

$\frac{1}{25} =0.04$ (Unusual)

Step-by-step explanation:

1/5 for one drawing

1/5 chance to win once, if there is only one game.

Then multiply them together to get 1/25.

If you need in decimal form 1/25 = 0.04 (unusual)

8 0

3 years ago

When Jim went to The Supreme Steak House, he had a meal costing $32.92. If the tax on the meal was 5%, what was the total cost o

sp2606 [1]

Take the total cost of the meal ($32.92) and multiply it by 5% (.05)
once you multiply those together you get how much tax is which is $1.65 (rounded up from 1.646)
now add that to your total and you get $34.57.

8 0

3 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.Tiles

Ugo [173]

By definition, the average rate of change is given by:

$AVR = \frac{f(x2)-f(x1)}{x2-x1}$

We evaluate each of the functions in the given interval.

We have then:

For f (x) = x ^ 2 + 3x:

Evaluating for x = -2:

$f (-2) = (-2) ^ 2 + 3 (-2)\\f (-2) = 4 - 6\\f (-2) = - 2$

Evaluating for x = 3:

$f (3) = (3) ^ 2 + 3 (3)\\f (3) = 9 + 9\\f (3) = 18$

Then, the AVR is:

$AVR = \frac{18-(-2)}{3-(-2)}$

$AVR = \frac{18+2}{3+2}$

$AVR = \frac{20}{5}$

$AVR = 4$

For f (x) = 3x - 8:

Evaluating for x =4:

$f (4) = 3 (4) - 8\\f (4) = 12 - 8\\f (4) = 4$

Evaluating for x = 5:

$f (5) = 3 (5) - 8\\f (5) = 15 - 8\\f (5) = 7$

Then, the AVR is:

$AVR = \frac{7-4}{5-4}$

$AVR = \frac{3}{1}$

$AVR = 3$

For f (x) = x ^ 2 - 2x:

Evaluating for x = -3:

$f (-3) = (-3) ^ 2 - 2 (-3)\\f (-3) = 9 + 6\\f (-3) = 15$

Evaluating for x = 4:

$f (4) = (4) ^ 2 - 2 (4)\\f (4) = 16 - 8\\f (4) = 8$

Then, the AVR is:

$AVR = \frac{8-15}{4-(-3)}$

$AVR = \frac{-7}{4+3}$

$AVR = \frac{-7}{7}$

$AVR = -1$

For f (x) = x ^ 2 - 5:

Evaluating for x = -1:

$f (-1) = (-1) ^ 2 - 5\\f (-1) = 1 - 5\\f (-1) = - 4$

Evaluating for x = 1:

$f (1) = (1) ^ 2 - 5\\f (1) = 1 - 5\\f (1) = - 4$

Then, the AVR is:

$AVR = \frac{-4-(-4)}{1-(-1)}$

$AVR = \frac{-4+4}{1+1}$

$AVR = \frac{0}{2}$

$AVR = 0$

Answer:

from the greatest to the least value based on the average rate of change in the specified interval:

f(x) = x^2 + 3x interval: [-2, 3]

f(x) = 3x - 8 interval: [4, 5]

f(x) = x^2 - 5 interval: [-1, 1]

f(x) = x^2 - 2x interval: [-3, 4]

4 0

3 years ago

Boxes hold various numbers of square-based prisms in a single column. The square base of each prism has a side length of 18 inch

Vinvika [58]

Answer:

$b(V) = \frac{V}{108}$

Step-by-step explanation:

The square base of each prism has a side length of 18 inches. The height of each prism, h, can be found using the function, where V is the volume of the prism.

So, V = 18² × h = 324h

⇒ h = $\frac{V}{324}$ .......... (1)

Now, given that the total height of the box, b, can be found using the function b(h) = xh, where x is the number of square-based prisms in a specific box.

Therefore, the box having 4 square prism will have height

b(h) = 3h

⇒ b(V) = $3 \times \frac{V}{324}$ {From equation (1)}

⇒ $b(V) = \frac{V}{108}$ (Answer)

8 0

3 years ago

Which hold closer to 3 liters, a puddle or a lake?<br><br> Answer ______________

maria [59]

A puddle

Explanation:
Let's think of it this way. You should drink 2 - 3 liters of water everyday, and you obviously aren't suppose to drink a lake amount of water everyday, so a puddle makes more sense.

3 0

3 years ago

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