37. we know the perimeter of the Box is 30 and two sides are five each so 30-10 is 20 divided by the other two equal size is 10 .
38, The dimension of other in the lids are 10 and a five to find the area if you multiply 10×5 = 50 and you only have to cover 42 sq cm so no you don't have enough eight more sq cm.
Solution:
As, You have Written Polygon ABCD is a rectangle.
It is a Four sided Polygon , having all it's interior angles equal to 90°.As well as Opposite sides are equal(AB=CD,AD=BC), equal diagonals(AC=B D).
Join any of the diagonal of Rectangle either AC or B D.
In Right Δ ABC , Right angled at B
---(1)
In Right Δ ADC , Right angled at D
---(2)
Adding (1) and (2) that is LHS to LHS and RHS to RHS
Ar( Δ ABC) +Ar( Δ ADC)![=\frac{1}{2}\times[ AB \times BC+ AD \times DC]\\\\=\frac{1}{2}[2 \times AB \times BC][\text{As, AB=CD, and BC=AD}]\\\\ = AB \times BC](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%5B%20AB%20%5Ctimes%20BC%2B%20AD%20%5Ctimes%20DC%5D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D%5B2%20%5Ctimes%20AB%20%5Ctimes%20BC%5D%5B%5Ctext%7BAs%2C%20AB%3DCD%2C%20and%20BC%3DAD%7D%5D%5C%5C%5C%5C%20%3D%20AB%20%5Ctimes%20BC)
So, Area of Rectangle= Product of any two Adjacent Sides
(x-5)(4x+1)
4x^2 times -5 is -20 the factors of -20 are -1x20, 1x-20... but to make the -19x you would add together the 1 and -20 because 1-20 is -19.
This then splits off to factorise 4x^2-20x, making this side 4x(1x-5) carry the brackets over to make it 1(1x-5) joining the brackets together to make (4x+1)(x-5)
Answer:um wow
Step-by-step explanation:
I do not know that one