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Dmitrij [34]
3 years ago
5

Pete drove 224 miles in 4 hours on saturday. If he drives at the same rate on Sunday, how long would it take him to drive 490 mi

les?
Mathematics
2 answers:
hoa [83]3 years ago
7 0

Answer:

8.75 hours

Step-by-step explanation:

What I do is form it into ratio form

224 : 4

490 : n

n is the hour we're trying to find

Since 490 isn't one of the multiples of 224, you divide 224 by itself, giving you 1

You then multiply 490 by 1 to get it

You divide and add again but with the hour (4)

4/224 = 0.0178... x 490 = 8.75 hours

There's how to get your answer

alisha [4.7K]3 years ago
3 0

Answer:

219.0496 m / s

Step-by-step explanation:

224 x 2 is 448 we still need 42 to get to 490 so, 224 divided by 4 is 56 since this is two much we can divide 56 by 2 to get 28. 28 plus 448 is 476 we need 14 more so 56 divided by 4 is 14 so 14 plus 476 is 490 finally we divide  and get 219.0496 m / s

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SpyIntel [72]
The formula for the sum of the a finite geometric series is this:
Sn = a((1-r^n) / (1-r))

The given values are:
n = 30
a = 0.5 mi
r = 1.10 (10% more each day)

S30 = 0.5 ((1-1.10^30) / (1-1.10))
S30 = 82.25 mi

After 30 days, he will have traveled 82.25 miles.
3 0
3 years ago
Find the value of 26/45 times 5/53 times 28/13 please show fingures and work
hjlf

\bf \cfrac{\stackrel{2}{~~\begin{matrix} 26 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{\underset{9}{~~\begin{matrix} 45 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{53}\cdot \cfrac{28}{~~\begin{matrix} 13 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies \cfrac{2\cdot 28}{9\cdot 53}\implies \cfrac{56}{477}

3 0
3 years ago
Please complete the system of equations.
kogti [31]

Answer:

x=-1,y=0

Step-by-step explanation:

-10y+9x=-9

10y+5x=-5

14x=-14

x=-1

-10y-9=-9

y=0

8 0
2 years ago
Question 10 The hypotenuse of a right triangle is I m longer than the longer leg. The other leg is 7 m shorter than the longer l
bonufazy [111]

Answer:

5, 12, 13

Step-by-step explanation:

let x be the longer leg then x + 1 is the hypotenuse and x - 7 the shorter leg

Using Pythagoras' identity in the right triangle

x² + (x - 7)² = (x + 1)² ← expand using FOIL

x² + x² - 14x + 49 = x² + 2x + 1

2x² - 14x + 49 = x² + 2x + 1 ( subtract x² + 2x + 1 from both sides )

x² - 16x + 48 = 0 ← in standard form

(x - 4)(x - 12) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x - 12 = 0 ⇒ x = 12

x = 4 , then x - 7 = 4 - 7 = - 3 ← not possible

x = 12, then x - 7 = 12 - 7 = 5 and x + 1 = 12 + 1 = 13

The lengths of the 3 sides are

longer leg = 12 m , shorter leg = 5 m and hypotenuse = 13 m

5 0
2 years ago
What is the leading coefficient of a third degree function that has an output of 221 when x=2, and has zeros of −15, 3i, and −3i
Vinil7 [7]

Answer:

  1

Step-by-step explanation:

The function with the given zeros will factor as ...

  f(x) = a(x +15)(x^2 +9) . . . . with leading  coefficient 'a'

You have ...

  f(2) = 221 = a(2+15)(2^2+9) = a(17)(13) = 221a

Then a = 221/221 = 1

The leading coefficient is 1.

_____

<em>Additional comment</em>

As you know, a function with zero x=p has a factor of (x -p). The given zeros mean the function has factors (x -(-15)), (x -3i). and (x -(-3i)). The product of the last two factors is the difference of squares: (x^2 -(3i)^2) = (x^2 -(-9)) = (x^2 +9). This is how we arrived at the factorization shown above.

3 0
2 years ago
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