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Dmitrij [34]
3 years ago
5

Pete drove 224 miles in 4 hours on saturday. If he drives at the same rate on Sunday, how long would it take him to drive 490 mi

les?
Mathematics
2 answers:
hoa [83]3 years ago
7 0

Answer:

8.75 hours

Step-by-step explanation:

What I do is form it into ratio form

224 : 4

490 : n

n is the hour we're trying to find

Since 490 isn't one of the multiples of 224, you divide 224 by itself, giving you 1

You then multiply 490 by 1 to get it

You divide and add again but with the hour (4)

4/224 = 0.0178... x 490 = 8.75 hours

There's how to get your answer

alisha [4.7K]3 years ago
3 0

Answer:

219.0496 m / s

Step-by-step explanation:

224 x 2 is 448 we still need 42 to get to 490 so, 224 divided by 4 is 56 since this is two much we can divide 56 by 2 to get 28. 28 plus 448 is 476 we need 14 more so 56 divided by 4 is 14 so 14 plus 476 is 490 finally we divide  and get 219.0496 m / s

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Above is a table with missing terms. Come up with a possible common difference that makes sense and list the missing terms.
Rina8888 [55]

Answer:

common ratio:2 2. 18  3.36  4.72 equation: 4.5(2^x)

Step-by-step explanation:

144=2*2*2*2*3*3    9=3*3

the common ratio would be 2

2. 9*2=18

3. 18*2=36

4. 36*2=72

(check) 72*2=144

0. 9/2=4.5

equation: 4.5(2^x)

7 0
3 years ago
You bought a pumpkin pie for Friendsgiving. At the end of the part 6/8 of the pumpkin pie was left. The host decided to share ou
ExtremeBDS [4]
The correct answer is D
6/8 divided by 4 is 3/16
6 0
3 years ago
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Plz help only have ten minutes ​
Anarel [89]

Answer:

-\frac{1}{2}

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
(2pm^-1q^0)^-4 • 2m ^-1 p^3 / 2pq^2
Montano1993 [528]

Answer:

\dfrac{m^3}{16p^2q^2}

Step-by-step explanation:

Given:

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}

1.

m^{-1}=\dfrac{1}{m}

2.

q^0=1

3.

2pm^{-1}q^0=2p\cdot \dfrac{1}{m}\cdot 1=\dfrac{2p}{m}

4.

(2pm^{-1}q^0)^{-4}=\left(\dfrac{2p}{m}\right)^{-4}=\left(\dfrac{m}{2p}\right)^4=\dfrac{m^4}{(2p)^4}=\dfrac{m^4}{16p^4}

5.

m^{-1}=\dfrac{1}{m}

6.

2m^{-1} p^3=2\cdot \dfrac{1}{m}\cdot p^3=\dfrac{2p^3}{m}

7.

\dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{\frac{2p^3}{m}}{2pq^2}=\dfrac{2p^3}{m}\cdot \dfrac{1}{2pq^2}=\dfrac{p^2}{mq^2}

8.

(2pm^{-1}q^0)^{-4}\cdot \dfrac{ 2m^{-1} p^3}{2pq^2}=\dfrac{m^4}{16p^4}\cdot \dfrac{p^2}{mq^2}=\dfrac{m^3}{16p^2q^2}

8 0
3 years ago
A padlock has the digits 0 through 9 arranged in a circle on its face. A combination for 0 1 2 3 4 6 5 7 8 9 this padlock is fou
stepan [7]

Answer:

The total numbers of possible combinations are 3430.

Step-by-step explanation:

Consider the provided information.

A combination for 0 1 2 3 4 6 5 7 8 9 this padlock is four digits long. Because of the internal mechanics of the lock, no pair of consecutive numbers in the combination can be the same or one place apart on the face.

Here, for the first digit we have 10 choices.

For the second digit we have 7 choices, as the digit can't be the same nor adjacent to the first digit.

For the third digit we have 7 choices, as the digit can't be the same nor adjacent to the second digit.

For the fourth digit we have 7 choices, as the digit can't be the same nor adjacent to the third digit.

So the number of choices are:

10\times 7\times 7\times 7=10\times 7^3\\10\times 343=3430

Hence, the total numbers of possible combinations are 3430.

8 0
3 years ago
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