Answer:
40 miles
Step-by-step explanation:
In the attached diagram, Point A is the starting point and C is the end point. We want to determine the distance from A to C.
The path driven forms a right triangle in which AC is the hypotenuse.
We therefore use the<u> Pythagorean Theorem</u> to solve for the AC.
Pythagorean Theorem: 

The straight line distance from the starting point is 40 miles.
Answer:
Option 3 is correct that is 
Step-by-step explanation:
We have general formula for sum of cube which is

Here, we have a=s and b=6
on substituting the values in the formula we will get

After simplification we will get

After rearranging the terms we will get
which exactly matches option 3 in the given options.
Therefore, option 3 is correct that is 
Answer:
a. is 1 and b is 2 and c is 3 I did it in algebra pay attention in class
Answer:

Step-by-step explanation:

Answer:
2
Step-by-step explanation:
Use the intercept method. Where is y when x = 0?