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Pie
2 years ago
13

A basket contains 3 apples, 3 peaches, and 4 pears. You randomly select a piece of fruit. It is an apple or a peach. What is the

probability?
Explanation on how you got the answer would be nice :)
Mathematics
1 answer:
hram777 [196]2 years ago
4 0

Answer:

1/10

one out of ten chance

Step-by-step explanation:

3 apples + 3 peaches + 4 pears = 10 fruit

if u pick A (emphasize the "A" meaning singular) fruit at random and it comes out as an apple or peach there is 10 fruit to possibly get and u got 1 peach or apple so if u end up - nevermind u get it i'm gunnu over complicate things tell me if u understand!

i was here first so brainliest?

if u get it but up to u!

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Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h
Delvig [45]

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899

So 2899 possible ways.

4 0
3 years ago
que condiciones debe cumplir las medidas de un triangulo para que puedas asegurar que es un triangulo rectangulo
nirvana33 [79]

Answer:

ENGLISH

One of the angles must equal 90 degrees and the other two angles must add up to 90 degrees.

SPANISH TRANSLATION

Uno de los ángulos debe ser igual a 90 grados y los otros dos ángulos deben sumar 90 grados.

3 0
2 years ago
2. 5 weeks 3 days =<br>days<br>​
Maru [420]

2.5 week 3 days = 20 days and 12 hours

2.5•7=17.5 17.5 +3 = 20.5

5 week 3 days = 38 days

5•7=35 35+3= 38 days

4 0
3 years ago
Read 2 more answers
After 4new students joined a class the class had 32students which equation can be used to find n the number of students in the c
Pani-rosa [81]

Answer:

n+4=32 is the answer

3 0
3 years ago
5. Lauren has $50 to spend at the Strawberry Festival. She spends $ 10 on admission and $12 on strawberry shortcake. She wants t
olga55 [171]

For this case we have that Lauren's initial amount of money was $ 50, if he spends $10 and $12 on admission and strawberry pie respectively we have:

$50 - ($10 + $12) = $50- $22 = $28

That is, she has $ 28 left

n: Let the variable that represents the amount of games Lauren can play.

Then, it must be fulfilled that:

0.75n \leq28\\n \leq \frac {28} {0.75}\\n \leq37.33

Thus, Lauren can play 37 times the game (at most)

ANswer:

n \leq37.33

Thus, Lauren can play 37 times the game (at most)

4 0
2 years ago
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