Find the -scores that bound the middle 96 of the area under the standard normal curve by using the TI-84 calculator.
1 answer:
Answer:

And
and if we use the following function on the Ti84 plus we got:
invNorm(0.02,0,1)
invNorm(1-0.02,0,1)
And the values with the middle 96% of the values are:

Step-by-step explanation:
For this case we want to find the limits with the middle 96% of the area below the normal curve, then the significance level would be:

And
and if we use the following function on the Ti84 plus we got:
invNorm(0.02,0,1)
invNorm(1-0.02,0,1)
And the values with the middle 96% of the values are:

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The answer is B
A. 6(a+5)
=6a+30 not equivalent to 6a+15
B.3(2a+5)
=6a+15 is equivalent
C.3(3a+12)
=9a+36 not equivalent
D.6(a+12)
=6a+72 not equivalent
So your answer is B
You take it like this=
8
-3
~~
3
+
3
+
3
-
1
~~
(4×2)
-
3
~~
[[5]]
《5+8》
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| 13 |
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Answer:
-2a-4n+14
Step-by-step explanation:
81 - 35+30 (55) = 26 therefore 26cm is ur final answer