What is the solution of the system of equations c + 4d = 8 and c = 4d - 6
2 answers:
C+3D=8
C=8-3D
C=4d-6
8 -3d =4d-6
8+6=4d+3D
14=7d
D=2
Rewrite the second equation in same form as the first So we have
c + 4d = 8
c - 4d = -6 Now add:-
2c + 0 = 2
2c = 2
c = 1
Now substitute c = 1 in the first equation:-
1 + 4d = 8
4d = 7
d = 7/4 = 1 3/4
Answer c = 1 and d = 1 3/4 Answer
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