Answer:
![\mu_{\hat{p}}=0.19](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%7Bp%7D%7D%3D0.19)
![\sigma_{\hat{p}}=0.0785](https://tex.z-dn.net/?f=%5Csigma_%7B%5Chat%7Bp%7D%7D%3D0.0785)
Step-by-step explanation:
We know that the mean and the standard error of the sampling distribution of the sample proportions will be :-
![\mu_{\hat{p}}=p](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%7Bp%7D%7D%3Dp)
![\sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}](https://tex.z-dn.net/?f=%5Csigma_%7B%5Chat%7Bp%7D%7D%3D%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D)
, where p=population proportion and n= sample size.
Given : The proportion of students at a college who have GPA higher than 3.5 is 19%.
i.e. p= 19%=0.19
The for sample size n= 25
The mean and the standard error of the sampling distribution of the sample proportions will be :-
![\mu_{\hat{p}}=0.19](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%7Bp%7D%7D%3D0.19)
![\sigma_{\hat{p}}=\sqrt{\dfrac{0.19(1-0.19)}{25}}\\\\=\sqrt{0.006156}=0.0784601809837\approx0.0785](https://tex.z-dn.net/?f=%5Csigma_%7B%5Chat%7Bp%7D%7D%3D%5Csqrt%7B%5Cdfrac%7B0.19%281-0.19%29%7D%7B25%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B0.006156%7D%3D0.0784601809837%5Capprox0.0785)
Hence , the mean and the standard error of the sampling distribution of the sample proportions :
![\mu_{\hat{p}}=0.19](https://tex.z-dn.net/?f=%5Cmu_%7B%5Chat%7Bp%7D%7D%3D0.19)
![\sigma_{\hat{p}}=0.0785](https://tex.z-dn.net/?f=%5Csigma_%7B%5Chat%7Bp%7D%7D%3D0.0785)
Answer:
Step-by-step explanation:
→ ![\frac{(7x^2-40x+52)}{(x^2-6x+9)}](https://tex.z-dn.net/?f=%5Cfrac%7B%287x%5E2-40x%2B52%29%7D%7B%28x%5E2-6x%2B9%29%7D)
→
→ ![\frac{7x^2-40x+52}{(x-3)^2}](https://tex.z-dn.net/?f=%5Cfrac%7B7x%5E2-40x%2B52%7D%7B%28x-3%29%5E2%7D)
<u>So, your answer is C</u>
<u></u>
<u></u>
<u>hope it helps...</u>
<u>have a great day!!</u>
2/3 divide by 5 is 2/15
Remember keep change flip
2/3 times 1/5 is 2/15
Hope this helps!
Answer:
f = -15
Step-by-step explanation:
Answer:
x=2, y=16
Step-by-step explanation:
x+y=18
y=8x
x+8x=18
x=2
y=16