It is called a difference of squares because there are two things squared being subtracted. You can recognize it when there are two terms, subtraction between the two of them, and you know the square root of both
<h3>
Answer: C) -1/2</h3>
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Explanation:
We'll apply the derivative to get
g(x) = 4x^3 + 3x^2
g ' (x) = 3*4x^2 + 2*3x
g ' (x) = 12x^2 + 6x
Set that equal to 0 and solve for x. We do this to find where the horizontal tangents are located.
g ' (x) = 0
12x^2 + 6x = 0
6x(2x + 1) = 0
6x = 0 or 2x+1 = 0
x = 0 or x = -1/2
Adding those two said solutions yields us the final answer choice C
<em>*Remember that y and f(x) are the same.</em>
With f(2), you are solving for the output (y), given that the input (x) is equal to 2.
With f(x) = 2, you are solving for the input (x), given that the output (y) is equal to 2.
Divide both sides by <span>t
</span>
<span>a+b=r/t
</span>Subtract b <span>from both sides
</span>
a<span>=r/t-b = Solution </span>