Question

Es of two children are 11 and 8 years.

Answer 1

Answer:

In 5 years the product of their ages will be 208

Step-by-step explanation:

The age of two children is 11 and 8 years.

Let's call x the number of years ahead.

We need to find when the product of their future ages is 208. The 11 years old child will be 11+x years old and the other child will be 8+x years, thus:

(11+x)(8+x)=208

Operating:

$88+11x+8x+x^2=208$

Simplifying:

$x^2+19x-120=0$

Factoring:

(x-5)(x+24)=0

Solving:

x=5, x=-24

The negative solution is not valid, thus x=5

In 5 years the product of their ages will be 208