9 times it will be 98 rhr
Its is two since you take out the decimals then divide regularly
Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
Answer:
Step-by-step explanation:
1. (6/a)x + 5 = 4
(6/a)x = -1
6x = -a
x = -a/6
2. 2ax + 7 = 13
2ax = 6
ax = 3
x = 3/a
3. -ax - 20 = -14
-ax = 6
x = -6/a
I’ll answer in just a quick min
