Answer:
The answer is D: 30 g.
Step-by-step explanation: I googled the answer to this question and it said that NHS reccomends that adults take around 30 g of fibre as a daily dose. If you take less, you may not get enough, but if you take more, you would possibly overdose. So, the answer is D: 30g.
Answer:
Harrison method results in more money after 2 years
Step-by-step explanation:
we know that
The compound interest formula is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
Harrison Method
![t=2\ years\\ P=\$300\\ r=0.02\\n=12](https://tex.z-dn.net/?f=t%3D2%5C%20years%5C%5C%20P%3D%5C%24300%5C%5C%20r%3D0.02%5C%5Cn%3D12)
substitute in the formula
![A=\$300(1+\frac{0.02}{12})^{12*2}=\$312.23](https://tex.z-dn.net/?f=A%3D%5C%24300%281%2B%5Cfrac%7B0.02%7D%7B12%7D%29%5E%7B12%2A2%7D%3D%5C%24312.23)
Sherrie Method
substitute in the formula
![A=\$200(1+\frac{0.04}{4})^{4*2}=\$216.57](https://tex.z-dn.net/?f=A%3D%5C%24200%281%2B%5Cfrac%7B0.04%7D%7B4%7D%29%5E%7B4%2A2%7D%3D%5C%24216.57)
therefore
Harrison method results in more money after 2 years
Answer:
15 degrees
Step-by-step explanation:
x + 5x + 90 =180( sum angle of a triangle )
6x + 90 = 180
6x = 180 - 90
6x = 90
x = 90/6
x = 15 degrees
<span>The question here is how much less Bella
spent in July than she budgeted. So firstly we have to know how much she
budgeted and how much she spent in order to know the difference. Her total
budgeted money is equal to $110.
On the other hand, her total expenditure is equal to $85.50. So the
difference between the two amounts is $24.5.</span>
Answer:
The required sample size is 171.
Step-by-step explanation:
Consider the provided information.
The engineer wants to estimate the average life within plus or minus 15 hours with 95 percent confidence. Assuming a process standard deviation of 100 hours,
First calculate the value of ![Z_{\frac{\alpha}{2}}](https://tex.z-dn.net/?f=Z_%7B%5Cfrac%7B%5Calpha%7D%7B2%7D%7D)
By using the table we get.
![Z_{\frac{\alpha}{2}}=1.96](https://tex.z-dn.net/?f=Z_%7B%5Cfrac%7B%5Calpha%7D%7B2%7D%7D%3D1.96)
Now use the formula: ![N=(\frac{Z_{\frac{\alpha}{2}}\times \sigma}{E})^2](https://tex.z-dn.net/?f=N%3D%28%5Cfrac%7BZ_%7B%5Cfrac%7B%5Calpha%7D%7B2%7D%7D%5Ctimes%20%5Csigma%7D%7BE%7D%29%5E2)
Substitute the respective values in the above formula we get.
![N=(\frac{1.96\times 100}{15})^2](https://tex.z-dn.net/?f=N%3D%28%5Cfrac%7B1.96%5Ctimes%20100%7D%7B15%7D%29%5E2)
![N=(\frac{1.96\times 100}{15})^2](https://tex.z-dn.net/?f=N%3D%28%5Cfrac%7B1.96%5Ctimes%20100%7D%7B15%7D%29%5E2)
![N=(\frac{196}{15})^2=170.73777](https://tex.z-dn.net/?f=N%3D%28%5Cfrac%7B196%7D%7B15%7D%29%5E2%3D170.73777)
Hence, the required sample size is 171.