True or false. indicate whether each comparison is true

Two cylinders are shown below which cylinder has a greater volume use 3.14 for pi

lesya [120]

Answer:

Cylinder Q has a greater volume

Step-by-step explanation:

For this question we need to utilise the volume of a cylinder which is

→ Volume of a cylinder = π × r² × h

Let's substitute in the values and then do the analysis

<u>Cylinder P</u>

→ Volume of a cylinder = π × r² × h

⇒ Substitute in the values

→ Volume of a cylinder = π × 4.25² × 14

⇒ Simplify

→ Volume of a cylinder = 794.430242277

<em>The volume of cylinder P is 794.430242277</em>

<u>Cylinder Q</u>

→ Volume of a cylinder = π × r² × h

⇒ Substitute in the values

→ Volume of a cylinder = π × 7² × 8.5

⇒ Simplify

→ Volume of a cylinder = 1308.47334022

<em>The volume of cylinder Q is 1308.47334022</em>

We can see that cylinder Q has a greater volume

8 0

3 years ago

2.24 Exit poll: Edison Research gathered exit poll results from several sources for the Wisconsin recall election of Scott Walke

iVinArrow [24]

Answer:

0.4929 = 49.29% probability that he voted in favor of Scott Walker

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Having a college degree.

Event B: Voting for Scott Walker.

They found that 57% of the respondents voted in favor of Scott Walker.

This means that $P(B) = 0.57$

Additionally, they estimated that of those who did vote in favor for Scott Walker, 33% had a college degree

This means that $P(A|B) = 0.33$

Probability of having a college degree.

33% of those who voted for Scott Walker(57%).

45% of those who voted against Scott Walker(100 - 57 = 43%). So

$P(A) = 0.33*0.57 + 0.45*0.43 = 0.3816$

What is the probability that he voted in favor of Scott Walker?

$P(B|A) = \frac{0.57*0.33}{0.3816} = 0.4929$

0.4929 = 49.29% probability that he voted in favor of Scott Walker

3 0

3 years ago

She is serving hot coffee and cold coffee in two rectangular-shaped tanks, each with dimensions width 8.75 inches, length 8.75 i

Blababa [14]

The volume of the coffee in each tank will be 1760. in³. The mass of cold coffee and hot coffee will be 6163.29 oz and 10213.45 oz. Then the number of the tank placed on a table is one only.

<h3>How to find the density and volume?</h3>

She is serving hot coffee and cold coffee in two rectangular-shaped tanks, each with dimensions width of 8.75 inches, a length of 8.75 inches, and a height of 23 inches.

The hot coffee has a density of 5.8 oz/in³ and the cold coffee has a density of 3.5 oz/ in³.

Then the volume of the coffee in each tank will be

We know that the dimension of both tanks is equal. Then the volume will remains equal.

Volume = L × B × H

Volume = 8.75 × 8.75 × 23

Volume = 1760.9375 ≅ 1760.94 in³

Then the mass of the coffee in each the tank will be

The mass of hot coffee will be

Mass = Density × Volume

Mass = 5.8 × 1760.94

Mass = 10213.45 oz

The mass of cold coffee will be

Mass = Density × Volume

Mass = 3.5 × 1760.94

Mass = 6163.29 oz

Then the number of the tank placed on a table is one only.

More about the density and volume link is given below.

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3 0

2 years ago

The gas co2 is diffusin at steady state through a tube 20 cm long having a diameter of 1 cm and containing n2 at 350 k . the tot

Marrrta [24]

The value is J = 1.71*10^-6 kmol/m^2.s

According to the given conditions we get,

The length the tube l= 0.20m

The diameter of the tube d= 0.01m

The total pressure inside the tube P= 101.32kPa

The partial pressure of CO2 at the first end is

P1= 456mm Hg = 60794.832 Pa

The partial pressure of CO2 at the other end is

P2= 76mm Hg = 10132.472 Pa

The temperature is T = 298 K

The diffusion coefficient D= 1.67* 10^-5 m^2/s

Generally the molar flux of CO2 is mathematically represented as

J= D{p1-p2} / R.T

Here R is the gas constant with value R= 8.314 j/kmol

So we get J= 1.71 * 10^-3 mol/m^2.sec

Learn more about Mole on:

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4 0

2 years ago

PLX ANSWER THIS!!! I BEG YOU. ASAP!!! THX!! =UwU=

kodGreya [7K]

It should be noted that the relationship is not linear based on the information illustrated as the difference between the numbers aren't the same.

<h3>How to illustrate the information?</h3>

It should be noted that an equation is simply used to illustrate and express the relationship between the variables.

It should be noted that for the relationship to be linear, it's essential that they've the same relationship between them.

When x = 1, y = 4.5. The

When x = 2, y = 6.5

When x = 3, y = 8.5

When x = 4 y = 11.5

It should be noted that there's a difference of 2 at first but between 3 and 4, there is. a difference of 3.

Therefore, the relationship is not linear.

Learn more about equations on:

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5 0

11 months ago