Answer:
Lee has 19 nickels and 8 dimes
Step-by-step explanation:
hello, I think I can help you with this
Step 1
Let
value of a nickel=$0.05
value of a dime=$0.10
number of nickels=N
number of nickels=D
According to the question data Lee has $1.75 in dimes and nickels.
0.05N+0.1D=1.75,equation(1)
also, the number of nickels is 11 more than the number of dimes.mathematical speaking
N=11+D,equation(2)
Step 2
replace N from equation (2) into equation (1)
0.05N+0.1D=1.75
0.05(11+D)+0.1D=1.75
Now, solve for D
0.55+0.05D+0.1D=1.75
0.15D=1.75-0.55
D=1.2/0.15
D=8
Step 3
replace the value of D into equation(2) to obtain N
N=11+8
N=11+8
N=19
Hence, Lee has 19 nickels and 8 dimes
Have a great day.
Answer:
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Step-by-step explanation:
Answer:
The answer is 3
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<u>I</u><u>f</u><u> </u><u>y</u><u>o</u><u>u</u><u> </u><u>r</u><u>e</u><u>a</u><u>l</u><u>l</u><u>y</u><u> </u><u>n</u><u>e</u><u>e</u><u>d</u><u> </u><u>h</u><u>e</u><u>l</u><u>p</u><u>,</u><u> </u><u>a</u><u>s</u><u>k</u><u> </u><u>a</u><u>n</u><u>y</u><u>t</u><u>i</u><u>m</u><u>e</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>I</u><u>'</u><u>l</u><u>l</u><u> </u><u>r</u><u>e</u><u>p</u><u>l</u><u>y</u><u> </u><u>a</u><u>s</u><u> </u><u>s</u><u>o</u><u>o</u><u>n</u><u> </u><u>a</u><u>s</u><u> </u><u>i</u><u> </u><u>c</u><u>a</u><u>n</u><u> </u><u>:</u><u>)</u>
3550 cds divided by 15 cds/ rack = 236.66667
Meaning that there will be 236 full racks and the last rack will only have 10 cds