Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
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Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
All you do is add up the sides of the walls, and you get your answer.
<3.
OG.
Answer:
3x-2y
Step-by-step explanation:
log10^(3x-2y)
We know the base is base 10 since it is not written
log10 10^(3x-2y)
The log10 10 cancels
3x-2y
Answer:
y=-15x+b
Step-by-step explanation:
Just move it around and use a calucator
