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charle [14.2K]
3 years ago
12

Solve eqaution 22p+11=4p-7

Mathematics
2 answers:
nadya68 [22]3 years ago
7 0
P is equal to negative one
stiv31 [10]3 years ago
3 0

Answer: -1

Step-by-step explanation:

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Find the perimeter of a triangle with side lengths of (3c + 4), (5c - 2), and (4c + 7)
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Answer:

12c +9 = Perimeter

Step-by-step explanation:

The perimeter of a triangle is found by adding all the sides

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12c +9 = Perimeter

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Jamie has 7/10 of a pound of chicken to cook for dinner if she's going to split the chicken between three people how much chicke
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3 years ago
Find the solution of the given initial value problem. ty' + 2y = sin t, y π 2 = 9, t > 0 y(t) =
Helen [10]

For the ODE

ty'+2y=\sin t

multiply both sides by <em>t</em> so that the left side can be condensed into the derivative of a product:

t^2y'+2ty=t\sin t

\implies(t^2y)'=t\sin t

Integrate both sides with respect to <em>t</em> :

t^2y=\displaystyle\int t\sin t\,\mathrm dt=\sin t-t\cos t+C

Divide both sides by t^2 to solve for <em>y</em> :

y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac C{t^2}

Now use the initial condition to solve for <em>C</em> :

y\left(\dfrac\pi2\right)=9\implies9=\dfrac{\sin\frac\pi2}{\frac{\pi^2}4}-\dfrac{\cos\frac\pi2}{\frac\pi2}+\dfrac C{\frac{\pi^2}4}

\implies9=\dfrac4{\pi^2}(1+C)

\implies C=\dfrac{9\pi^2}4-1

So the particular solution to the IVP is

y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac{\frac{9\pi^2}4-1}{t^2}

or

y(t)=\dfrac{4\sin t-4t\cos t+9\pi^2-4}{4t^2}

6 0
3 years ago
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