Question: solve for r: 6 ^ (2r) = 800
Answer: 1.87
Step-by-step explanation:
6 ^ (2r) = 800
log(6 ^ (2r)) = log(800)
2r log(6) = log(800)
r = log(800) / (2 log(6))
r = 1.86537641979
round
r = 1.87
log can be any logarithm function.
6^(2×1.86) = 784.734328546
6^(2×1.87) = 813.365367336
Answer:
Dennis paid $82 and Connie paid $46.
Step-by-step explanation:
We can set up an equation by putting in variables, c representing how much Connie paid. Since we know that Dennis paid $36 more, we will also factor that in the equation.
c + c + 36 = 128
Where c + 36 represents the amount Dennis paid, and 128 represents the total amount paid as given in the question. We can start by adding like terms. 2c + 36 = 128
Now, we can subtract 36 from each side,
2c + 36 - 36 = 128 - 36
2c = 92
Divide each side by two,
2c/2 = 92/2
c = 46
Now, to make sure this is correct, let's substitute our c for 46 in our equation:
46 + 46 + 36 = 128
92 + 36 = 128
128 = 128
Therefore, our equation is correct, and Dennis paid $82 while Connie paid $46.
Answer:
times it
Step-by-step explanation:
Answer:
x +5
Step-by-step explanation:
5x-2+3x+4+2x+9
5x-2x=3x
3x-3x=x
-2+2=0
0+4=4
4-9 =5
Step-by-step explanation:
1)x is less than 7
2)x is greater than and equal to -4
