Need help on 2 plz help me show your work and answer in struggling
1 answer:
You might be interested in
Answer:
y = 6, z = 3
Substitute values into the expression:
Simplify both fractions:
Add the fractions:
[tex]\frac{8}{9}
Hello!
We can go through each equation to solve:
1.
x + 3 = 4(x - 1) + 2
Distribute the coefficient outside of the parenthesis:
x + 3 = 4(x) + 4(-1) + 2
Simplify:
x + 3 = 4x - 4 + 2
x + 3 = 4x - 2
Subtract x from both sides:
3 = 3x - 2
Add 2 to both sides:
5 = 3x
Divide both sides by 3:
5/3 = x. This is not the answer.
2.
2x - 8 = 7 - 3x
Add 3x to both sides:
5x - 8 = 7
Add 8 to both sides:
5x = 15
Divide both sides by 5:
5x/5 = 15/5
x = 3. This is an answer.
3.
3(x + 2) = 14 - x
Distribute:
3(x) + 3(2) = 14 - x
3x + 6 = 14 - x
Add x to both sides:
4x + 6 = 14
Subtract 6 from both sides:
4x = 8
Divide both sides by 4:
4x/4 = 8/4
x = 2. This is not an answer.
4.
4(x - 1) = x + 5
Distribute:
4x - 4 = x + 5
Subtract x from both sides:
3x - 4 = 5
Add 4 to both sides:
3x = 9
Divide both sides by 3:
3x/3 = 9/3
x = 3. This is an answer.
5.
5 - 2(x + 1) = x
Distribute:
5 - 2x - 2 = x
Simplify:
3 - 2x = x
Add 2x to both sides:
3 = 3x
Divide both sides by 3:
3/3 = 3x/3
x = 1. This is not an answer.
6.
6(x - 4) = 2x
Distribute:
6x - 24 = 2x
Subtract 6x from both sides:
-24 = -4x
Divide both sides by -4:
-24/(-4) = -4x/(-4)
x = 6. This is not an answer.