Question

The sides of the rectangle are in the ratio of 4:7. If its length is 31.5 in., find the width, the perimeter, and the area of this rectangle.

Answer 1

Let $\ell$ the length and $w$ the width. By the ratio of the sides:

$\dfrac{w}{\ell}=\dfrac{4}{7}\Longrightarrow \dfrac{w}{31.5}=\dfrac{4}{7}\Longrightarrow w=\dfrac{4\cdot31.5}{7}\Longrightarrow \boxed{w=18~in.}$

Now, we'll find the perimeter p. We'll use the formula below:

$p=2(\ell+w)\\\\ p=2(31.5+18)\\\\ p=2\cdot49.5\\\\ \boxed{p=99~in.}$

The area of a rectangle is $S=w\cdot\ell$. Then:

$S=w\cdot\ell\\\\ S=18\cdot31.5\\\\ \boxed{S=567~in.^2}$

Answer 2

Answer:

width=18

Step-by-step explanation:

So im not gonna give you the full everything but you get the width by doing (4/7)31.5  and that equals you answer which in this case is 18