Answer:
midpoint (5,4)
Step-by-step explanation:
The midpoint(M) of a segment with endpoints (x₁ , y₁) and ( x₂, y₂) is
where x₁ = 2 and x₂ = 8
y₁ = 0 and y₂ = 8
M = 
M = 
M = 5 , 4
She is going to 5 classes 3×5 = 15 and 15÷3=5
Let J = rate of jet in still airLet W = rate of wind Distance formula: d = rt / r = d/t Flying against the wind the jet flies at a rate of J - W = 1860 miles/3 hours = 620 miles per hourFlying with the wind the jet flies at a rate of J+W = 9180 miles/9 hours = 1020 miles per hour The average of these 2 rate is the speed of the jet in still air J = (620+1020)/2 = 820 miles per hour J - W = 620
820 - W = 620
W = 820 - 620 = 200 miles per hour The jet in still air flies at a rate of 820 mph(miles per hour)The wind speed is 200 mph(miles per hour)
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