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Sergeeva-Olga [200]
3 years ago
8

Find the difference.... 23/4-12/4

Mathematics
2 answers:
KatRina [158]3 years ago
5 0
The answer would be 11/4 you'd just subtract 12 from 23. 23-12 = 11
Nadusha1986 [10]3 years ago
4 0
-1.5625 thats what i go idk if thats what your looking for?
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Use Long Division to answer number 4. Please show all work!​
skelet666 [1.2K]

Answer:

2x² + 3x + 4 + (17x + 9) / (x² − 4)

Step-by-step explanation:

Start by setting up the division.  Make sure to write all the coefficients, even the zero ones.

x² + 0x − 4 | 2x⁴ + 3x³ − 4x² + 5x − 7

Start by dividing the first term of the dividend (2x⁴) by the first term of the divisor (x²).  That's 2x²; it'll be the first term in quotient.  Multiply the divisor by 2x²:

2x⁴ + 0x³ − 8x²

Subtract that from the first three terms of the dividend:

3x³ + 4x²

Drop down the next term from the dividend, and start the process all over again.

3x³ + 4x² + 5x

When you finish, the quotient will be 2x² + 3x + 4, and the remainder will be 17x + 9.

4 0
3 years ago
Find the center of a circle with the equation: x^2 + y^2 - 2y - 8x - 19 = 0
777dan777 [17]

Answer:

(4, 1)

Step-by-step explanation:

x^2 + y^2 - 2y - 8x - 19 = 0

We rearrange the terms and complete the square twice.

x^2 - 8x + y^2 - 2y = 19

x^2 - 8x + 16 + y^2 - 2y + 1 = 19 + 16 + 1

(x - 4)^2 + (y - 1)^2 = 6^2

The center is (4, 1)

3 0
3 years ago
Um taxista cobra R$ 15,00 pela bandeirada mais R$ 0,80 por quilômetro rodado. Qual é o preço a ser pago por uma corrida de 100 q
Anika [276]

Answer:

can u wrote this question in english .Because I don´t understand this languages

6 0
3 years ago
Read 2 more answers
How do I solve this
Drupady [299]

Answer:

-17z + 15a

Step-by-step explanation:

can't be simplied

answer:

-17z + 15a

7 0
4 years ago
Read 2 more answers
Find the equation of the line passing through the points (-3,8) and (3,-4). Write the
VLD [36.1K]

Answer:

y = -2x + 2

Step-by-step explanation:

(-4-8)/(3-(-3)) = -12/6 = -2

-4 = -2(3) + b

-4 = -6 + b

b = 2

6 0
3 years ago
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