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jasenka [17]
3 years ago
13

Which expression shows the result of applying the distributive property to 3(1/2x - 1/7)

Mathematics
1 answer:
AveGali [126]3 years ago
8 0
The answer is 3/2x - 3/7
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Given the rule, find the 8th term in the arithmetic<br> sequence.<br> an =3n + 4
dybincka [34]

Answer:

You simply substitute 8 for n

A₈ =3(8)+4=28

4 0
2 years ago
There is only three options someone help
Pepsi [2]

Answer:

Answer is Option 2

Step-by-step explanation:

Triangles equal to 180 degrees in total. So it is 55+54+x+74=180

The simplified version that I just wrote is Option 2

7 0
3 years ago
I need help with question number one please help?
Kisachek [45]
1) Area of trapezoid =1/2(base 1 +base 2)* height

A= \frac{23 \frac{1}{3}+4 \frac{2}{3}  }{2} *(12 \frac{3}{4} ) =  \frac{27 \frac{3}{3} }{2} *( \frac{51}{4} ) =  \frac{28}{2} * \frac{51}{4} =  \frac{7*51}{2} = \frac{357}{2} =178 \frac{1}{2}  x^{2}

5 0
3 years ago
Find the smallest 4 digit number such that when divided by 35, 42 or 63 remainder is always 5
alex41 [277]

The smallest such number is 1055.

We want to find x such that

\begin{cases}x\equiv5\pmod{35}\\x\equiv5\pmod{42}\\x\equiv5\pmod{63}\end{cases}

The moduli are not coprime, so we expand the system as follows in preparation for using the Chinese remainder theorem.

x\equiv5\pmod{35}\implies\begin{cases}x\equiv5\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{42}\implies\begin{cases}x\equiv5\equiv1\pmod2\\x\equiv5\equiv2\pmod3\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{63}\implies\begin{cases}x\equiv5\equiv2\pmod 3\\x\equiv5\pmod7\end{cases}

Taking everything together, we end up with the system

\begin{cases}x\equiv1\pmod2\\x\equiv2\pmod3\\x\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

Now the moduli are coprime and we can apply the CRT.

We start with

x=3\cdot5\cdot7+2\cdot5\cdot7+2\cdot3\cdot7+2\cdot3\cdot5

Then taken modulo 2, 3, 5, and 7, all but the first, second, third, or last (respectively) terms will vanish.

Taken modulo 2, we end up with

x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod2

which means the first term is fine and doesn't require adjustment.

Taken modulo 3, we have

x\equiv2\cdot5\cdot7\equiv70\equiv1\pmod3

We want a remainder of 2, so we just need to multiply the second term by 2.

Taken modulo 5, we have

x\equiv2\cdot3\cdot7\equiv42\equiv2\pmod5

We want a remainder of 0, so we can just multiply this term by 0.

Taken modulo 7, we have

x\equiv2\cdot3\cdot5\equiv30\equiv2\pmod7

We want a remainder of 5, so we multiply by the inverse of 2 modulo 7, then by 5. Since 2\cdot4\equiv8\equiv1\pmod7, the inverse of 2 is 4.

So, we have to adjust x to

x=3\cdot5\cdot7+2^2\cdot5\cdot7+0+2^3\cdot3\cdot5^2=845

and from the CRT we find

x\equiv845\pmod2\cdot3\cdot5\cdot7\implies x\equiv5\pmod{210}

so that the general solution x=210n+5 for all integers n.

We want a 4 digit solution, so we want

210n+5\ge1000\implies210n\ge995\implies n\ge\dfrac{995}{210}\approx4.7\implies n=5

which gives x=210\cdot5+5=1055.

5 0
2 years ago
I need help with finding out what the answer is 6=-w/8
tatyana61 [14]

6 = -w/8

  • Multiply both sides by 8.

48 = -w

  • Divide both sides by -1.

w = -48 is your answer.

3 0
3 years ago
Read 2 more answers
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