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WITCHER [35]
4 years ago
10

Solve 62^(x+3)<=7^(2x+1)

Mathematics
1 answer:
ddd [48]4 years ago
6 0
62^{x+3}\leq7^{2x+1}\\&#10;\ln 62^{x+3}\leq\ln 7^{2x+1}\\&#10;(x+3)\ln 62\leq (2x+1)\ln 7\\&#10;x\ln 62+3\ln 62\leq2x\ln 7+\ln 7\\&#10;x\ln 62-2x\ln 7\leq\ln 7-3\ln 62\\&#10;x(\ln 62-2\ln7)\leq \ln 7-3\ln 62\\&#10;x\leq\dfrac{\ln 7-3\ln 62}{\ln 62-2\ln7}
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