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amid [387]
3 years ago
10

8x - 3(x - 1) = 2x + 6 solve for x and show work

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
7 0

Answer:

x = 3

Step-by-step explanation:

8x - 3(x - 1) = 2x + 6

simplify

8x - 3x + 3 = 2x + 6

add like terms

5x + 3 = 2x + 6

subtract 2x from both sides

3x + 3 = 6

subtract 3 from both sides

3x = 3

divide by 3

x = 3

Lena [83]3 years ago
6 0

Answer:

x= 1

Step-by-step explanation:

open brackets first

8x - 3x + 3 = 2x + 6

Calculate

5x+3= 2x+6

transpose the like terms

5x-2x= 6-3

calculate

3x= 3

x= 3/3

x= 1

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The number 49 has exactly three factors. Since 98 is a multiple of 49, which must be true of 98? It must have only two factors.
Mumz [18]

Answer:

Step-by-step explanation:

⇒49=7×7 =1 × 49

Factors of 49 = 1,7,49

⇒It is given that ,98 is a Multiple of 49.

98 = 49 × 2

So, apart from factors of 49, number 2, and 98 are also included in the set of factors of 98.

→Factors of 98 are =1,2,7,49,98

3 0
3 years ago
Victoria is a manager at a makeup company. She has two makeup artists, Taylor and Lauren. Taylor can complete a large project in
Vladimir [108]
The rate of how many projects Taylor can complete can be modeled at x/6 and Brianne can be modelled as x/8. So, by combining the functions and setting equal to 1, you can solve. 

x/6 + x/8 = 1

You have to give common demoninators

4x/24 + 3x/24 = 1

Then add together and cross multiply. Giving you an answer of 24/7 or roughly 3.43 hours when rounded to the nearest hundredth. 
8 0
3 years ago
The solution set for 7q2 − 28 = 0 is
nevsk [136]

Answer:

2 and -2

Step-by-step explanation:

● 7q^2 -28 = 0

Add 28 to both sides

● 7q^2-28+28 = 28

● 7q^2 = 28

Divide both sides by 7

●7q^2/7 = 28/7

● q^2 = 4

You can write directly q= 2 or q= -2

To understand it use the absolute value.

● |q| = 2

● q = 2 or q = -2

The solutions are {2, -2}

5 0
4 years ago
What conjecture can you make about the sum of the first 30 odd numbers
adoni [48]
It will be an even number!
5 0
4 years ago
(10.02)
ollegr [7]
<h2>Hello!</h2>

The answer is:

C. Cosine is negative in Quadrant III

<h2>Why?</h2>

Let's discard each given option in order to find the correct:

A. Tangent is negative in Quadrant I: It's false, all functions are positive in Quadrant I (0° to 90°).

B. Sine is negative in Quadrant II: It's false, sine is negative in positive in Quadrant II. Sine function is always positive coming from 90° to 180°.

C. Cosine is negative in Quadrant III. It's true, cosine and sine functions are negative in Quadrant III (180° to 270°), meaning that only tangent and cotangent functions will be positive in Quadrant III.

D. Sine is positive in Quadrant IV: It's false, sine is negative in Quadrant IV. Only cosine and secant functions are positive in Quadrant IV (270° to 360°)

Have a nice day!

6 0
4 years ago
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