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Katen [24]
3 years ago
8

Write an algorithm that prints out all the subsets of 3 elements of a set of n elements. The elements of the set are stored in a

list that is the input to the algorithm, (you may assume all elements in the list are distinct. The list can be an array). Algorithm: Print_3_Element_Subsets Input: List S of n distinct elements. Output: Print out all 3-element subsets of S. void Print_3_Element_Subsets (int n, const element_type S[])
Computers and Technology
1 answer:
Ksenya-84 [330]3 years ago
7 0

void Print_3_Element_Subsets(int n,const element_type S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

print("No subset found");

}

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

print(S[i],S[j],S[k]);

}

}

}

}

C++ Implementation;

#include<cstdlib>

#include<time.h>

using namespace std;

int S1[5]= {1,2,3,4,5};

int n1 = 5;

int S2[2]={1,2};

int n2 = 2;

void Print_3_Element_Subsets(int n,const int S[])

{

if(n<3) // condition to check if list have less than 3 elements

{

printf("No subset found\n");

}

printf("3 Subsets are\n");

for(int i =0; i < n ; i++)

{

for(int j =i+1; j < n ; j++)

{

for(int k =j+1; k < n ; k++)

{

cout<<S[i]<<" "<<S[j]<<" "<<S[k]<<endl;

}

}

}

}

int main()

{

cout<<"Case 1"<<endl;

Print_3_Element_Subsets(n1,S1);

cout<<endl<<"Case 2"<<endl;

Print_3_Element_Subsets(n2,S2);

}

OUTPUT

Case 1

3 Subsets are

1 2 3

1 2 4

1 2 5

1 3 4

1 3 5

1 4 5

2 3 4

2 3 5

2 4 5

3 4 5

Case 2

No subset found

3 Subsets are

--------------------------------

Process exited after 0.0137 seconds with return value 0

Press any key to continue . . .

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Further Explanation:

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write a program that keeps names and email addresses in a dictionary as key-value pairs. the program should display a menu that
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To write a program that keeps names and email addresses in a dictionary as key-value pairs check the code given below.

<h3>What is key-value pairs?</h3>

In a key-value pair, two related data elements are combined: a value, which is a variable that belongs to the set (for example, male/female, green, 100), and a key, which is a constant that defines the data set (for example, gender, color, price).

A key-value pair could look something like this when fully formed:

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↓↓↓//<u>Python code</u>//↓↓↓

import pickle

import sys

try:

   f=open('email.dat','rb')

   d=pickle.load(f)  

   f.close()

     

except:    

   d={}

while True:

   print('\n1. Find a email address')

   print('2. Add name and email address')

   print('3. Change an email address')

   print('4. Delete an email address')

   print('5. Exit\n')

   choice=input('\nEnter a choice: ')

   if choice:

       choice=int(choice)

   else:

       print('\nEnter a number')

       continue    

   if choice == 1:

       while True:

           name=input('\nEnter the name ')

           if name:

               if name in d:

                   print('\n%s is the email id of %s \n' % (d[name],name))

                   break

               else:

                   print('\n Email not found \n')

                   break

           else:

               print('\nName cannot be empty\n')

               continue

           

   elif choice==2:

       while True:            

       

           name=input('\nEnter the name ')

           if name:

               break;

           else:

               print('\nName cannot be empty \n')

               continue

       while True:            

       

           email=input('\nEnter the email address ')

           if email:

               d[name]=email

               break

           else:

               print('\nEmail cannot be empty\n')

               continue

           

   elif choice==3:

       while True:            

       

           name=input('\nEnter the name to change the email address ')

           if name:

               if name in d:

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                   d[name]=email

                   print('\nEmail address changed \n')

                   break;

               else:

                   print('\nName not found \n')

                   break

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               continue

           

   elif choice == 4:

       while True:            

       

           name=input('\nEnter the name to remove ')

           if name:

               if name in d:

                   del d[name]

                   print('\nName and Email address removed \n ')

                   break;

               else:

                   print('\nName not found \n')

                   break

           else:

               print('\nName cannot be empty\n')

               continue

   elif choice == 5:

       

       f=open('email.dat','wb')

       pickle.dump(d,f)

       f.close()

       sys.exit()

   else:

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Learn more about key-value pair

brainly.com/question/29414672

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3 0
1 year ago
4. When the keyword ____________________ is followed by a parenthesis, it indicates a call to the superclass constructor.
Andreyy89

Answer:

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Basically, all instance variables that have been used or declared in any superclass would be present in its subclass object.

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