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Dmitrij [34]
3 years ago
5

An extremely simple (and surely unreliable) weather prediction model would be one where days are of two types: sunny or rainy. A

sunny day is 90% likely to be followed by another sunny day, and a rainy day is 50% likely to be followed by another rainy day. Model this as a Markov chain. If Sunday is sunny, what is the probability that Tuesday (two days later) is also sunny
Mathematics
1 answer:
andrezito [222]3 years ago
7 0

Answer:

The probability that if Sunday is sunny, then Tuesday is also sunny is 0.86.

Step-by-step explanation:

Let us denote the events as follows:

Event 1: a sunny day

Event 2: a rainy day

From the provided data we know that the transition probability matrix is:

                 \left\begin{array}{ccc}1&\ \ \ \ 2\end{array}\right

\text{P}=\left\begin{array}{c}1&2\end{array}\right  \left[\begin{array}{cc}0.90&0.10\\0.50&0.50\end{array}\right]

In this case we need to compute that if Sunday is sunny, what is the probability that Tuesday is also sunny.

This implies that we need to compute the value of P₁₁².

Compute the value of P² as follows:

P^{2}=P\cdot P

     =\left[\begin{array}{cc}0.90&0.10\\0.50&0.50\end{array}\right]\cdot \left[\begin{array}{cc}0.90&0.10\\0.50&0.50\end{array}\right]\\\\=\left[\begin{array}{cc}0.86&0.14\\0.70&0.30\end{array}\right]

The value of P₁₁² is 0.86.

Thus, the probability that if Sunday is sunny, then Tuesday is also sunny is 0.86.

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Basile [38]

Answer:  The answer would be 1/2

Step-by-step explanation:

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<em>It is a linear equation meaning equation of a straight line. </em>

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<em>next, y varies directly as x. If y = 15 when x = 60, find y when x = 100 </em>

<em>if y= 15, when x=60, then there is a number m such that m*y= 60 </em>

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<em>so the equation is y=4x. in this cause, the b=0 </em>

<em>so when x=0, y=0 </em>

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<em>Please give me Brainliest</em>

4 0
3 years ago
Read 2 more answers
Please show your work
Effectus [21]
Here hope this help the solution is X= -2 and y=9

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2 years ago
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Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

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⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

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\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

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Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

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5 0
1 year ago
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sergeinik [125]

Answer:

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Finger [1]

We have a prism with a volume of 16y⁴ + 16y³ + 48y² cubic units.

Its volume is equal to the area of its base times its height.

Of course, for those to be the base area and height of this prism, they would have to multiply to 16y⁴ + 16y³ + 48y² cubic units.

Let's test each of these answers to see which gives us the correct volume.

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We find the volume by multiplying the base area by the height...

4y(4y² + 4y + 12)

Distribute the 4y to each term inside the parentheses.

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This is not the right volume, so these can not be dimensions of our prism.

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We find the volume by multiplying the base area by the height...

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Distribute the 8y² to each term inside the parentheses.

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This is not the right volume, so these can not be dimensions of our prism.

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We find the volume by multiplying the base area by the height...

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Distribute the 12y to each term inside the parentheses.

48y³ + 48y² + 432y

This is not the right volume, so these can not be dimensions of our prism.

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a base area of 16y² square units and height of y² + y + 3 units

We find the volume by multiplying the base area by the height...

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Distribute the 16y² to each term inside the parentheses.

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The volume fits, so these could be the base area and height of our prism.

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D. a base area of 16y² square units and height of y² + y + 3 units

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7 0
3 years ago
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