Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.
![\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7Bhyperbolas%2C%20horizontal%20traverse%20axis%20%7D%20%5C%5C%5C%5C%20%5Ccfrac%7B%28x-%20h%29%5E2%7D%7B%20a%5E2%7D-%5Ccfrac%7B%28y-%20k%29%5E2%7D%7B%20b%5E2%7D%3D1%20%5Cqquad%20%5Cbegin%7Bcases%7D%20center%5C%20%28%20h%2C%20k%29%5C%5C%20vertices%5C%20%28%20h%5Cpm%20a%2C%20k%29%5C%5C%20c%3D%5Ctextit%7Bdistance%20from%7D%5C%5C%20%5Cqquad%20%5Ctextit%7Bcenter%20to%20foci%7D%5C%5C%20%5Cqquad%20%5Csqrt%7B%20a%20%5E2%20%2B%20b%20%5E2%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
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Answer:
Step-by-step explanation:
Add or subtract multiples of 360° to find coterminal angles.
<u>Positive</u>
75° +360° = 435°
75° +2×360° = 795°
<u>Negative</u>
75° -360° = -285°
75° -2×360° = -645°
The answer is c = .6x + 5
In order to find the equation, note that the price per pound is contingent upon the weight in x. Therefore, we can multiply the two together.
We also need to add the constant, which is 5.
Answer:
A) is correct
Step-by-step explanation:
If you would like to know how many centimeters should you cut off, you can calculate this using the following steps:
1 1/2 meters = 3/2 meters = 1.5 meters = 150 centimeters
250 centimeters - 1 1/2 meters = 250 centimeters - 150 centimeters = 100 centimeters = 1 meter
The correct result would be 100 centimeters.
