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____ [38]
3 years ago
15

Which inequality best represents the situation that players on the junior varsity football team must weigh more than 119 pounds?

Mathematics
2 answers:
olga_2 [115]3 years ago
7 0
The answer is A cuz it’s pointing right, which is greater than 119
pishuonlain [190]3 years ago
4 0

Answer:

The answer is option A

Step-by-step explanation:

The <em>problem has 4 options</em>, <u>each of them showing a Real Number straight line</u>. In every line we see one part with black colour, one part with blue colour and a blue dot (empty or full).

To solve the problem we have to know that in a straight line of Real Numbers, if we want to colour a set of numbers greater than a specific number, we will have to colour the line begining in that number, and all the way to the right (to infinity). Besides, as we need a set greater than that number, that number shouldn't be included in the set (this is noted with an empty dot, with the same colour of the coloured line).

In the options, the empty dot means that the number is not included, so <em>the option A has the blue line to the right, and has a blue dot over 119 that is empty</em>.

Option A is the correct answer.

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Factor 2a2b3 - 14ab + 16a
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Step-by-step explanation:

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2 Probability and Stats questions!!
mart [117]
 1) To find the confidence interval 
the sample mean x = 38     σ = 9; n = 85;
The confidence level is 95% (CL = 0.95) <span>CL = 0.95
so α = 1 – CL = 0.05   
</span><span>α/2 = 0.025   </span>Z(α/2) = z0.025  
The area to the right of Z0.025 is 0.025 and the area to the left of Z0.025 is 1 – 0.025 = 0.975
Z(α/2) = z0.025 = 1.645 This can be found using a computer, or using a probability table for the standard normal distribution.
<span>EBM = (1.645)*(9)/(85^0.5)=1.6058</span> x - EBM = 38 – 1.6058 = 36.3941 <span> x + EBM = 38 + 1.6058 = 39.6058
</span>The 95% confidence interval is (36.3941, 39.6058).
The answer is the letter D
<span>The value of 40.2 is <span>within the 95% confidence interval for the mean of the sample

</span></span>2) To find the confidence interval  <span>
<span>the sample mean x = </span>76     σ = 20; n = 102; </span><span>
The confidence level is 95% (CL = 0.95) CL = 0.95 
so α = 1 – CL = 0.05   
α/2 = 0.025   Z(α/2) = z0.025 
The area to the right of Z0.025 is 0.025 and the area to the left of Z0.025 is 1 – 0.025 = 0.975 
Z(α/2) = z0.025 = 1.645 This can be found using a computer, or using a probability table for the standard normal distribution.
EBM = (1.645)*(20)/(102^0.5)=3.2575 x - EBM = 76 – 3.2575 = 72.7424 </span>  x + EBM = 76 + 3.2575 = 79.2575 <span> 
The 95% confidence interval is (</span>72.7424 ,79.2575).<span>
The answer is the letter </span>A and the letter D<span>
The value of 71.8 and 79.8 <span> are </span> outside<span> the 95% confidence interval for the mean of the sample</span></span>
5 0
3 years ago
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