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____ [38]
3 years ago
15

Which inequality best represents the situation that players on the junior varsity football team must weigh more than 119 pounds?

Mathematics
2 answers:
olga_2 [115]3 years ago
7 0
The answer is A cuz it’s pointing right, which is greater than 119
pishuonlain [190]3 years ago
4 0

Answer:

The answer is option A

Step-by-step explanation:

The <em>problem has 4 options</em>, <u>each of them showing a Real Number straight line</u>. In every line we see one part with black colour, one part with blue colour and a blue dot (empty or full).

To solve the problem we have to know that in a straight line of Real Numbers, if we want to colour a set of numbers greater than a specific number, we will have to colour the line begining in that number, and all the way to the right (to infinity). Besides, as we need a set greater than that number, that number shouldn't be included in the set (this is noted with an empty dot, with the same colour of the coloured line).

In the options, the empty dot means that the number is not included, so <em>the option A has the blue line to the right, and has a blue dot over 119 that is empty</em>.

Option A is the correct answer.

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A rectangle has a perimeter of 42 feet. Its length, L, is three feet more than twice its width, W. Create a equation that relate
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Answer:

W = 6 feet

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Step-by-step explanation:

The perimeter of the rectangle is the length of the outer boundary.

If length is defined as L and width is defined as D,

Perimeter = 2(L + W)

Perimeter is given to be 42 feet.

2(L + W) = 42

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7 0
3 years ago
can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylind
shutvik [7]

the new radius be to meet the client's need is 4.9 cm .

<u>Step-by-step explanation:</u>

Here we have , can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylindrical can that has the same volume but is 15 cm tall. We need to find What must the new radius be to meet the client's need . Let's find out:

Let we have two cylinders of volume V_1 , V_2 with parameters as follows :

r_1=6cm\\h_1=10cm\\r_2=?\\h_2=15cm

We know that volume of cylinder is \pi r^2h , According to question volume of both cylinder is equal i.e

⇒ V_1=V_2

⇒ \pi (r_1)^2h_1= \pi (r_2)^2h_2

⇒ (r_1)^2h_1= (r_2)^2h_2

⇒ \frac{(r_1)^2h_1}{h_2}= (r_2)^2

⇒ (r_2) =\sqrt{ \frac{(r_1)^2h_1}{h_2}}                   Putting all values

⇒ (r_2) =\sqrt{ \frac{(6)^2(10)}{15}}

⇒ (r_2) =\sqrt{ \frac{36(10)}{15}}

⇒ (r_2) =\sqrt{ \frac{360}{15}}

⇒ (r_2) =\sqrt{24}

⇒ (r_2) =4.9cm

Therefore , the new radius be to meet the client's need is 4.9 cm .

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