The table is missing in the question. The table is provided here :
Group 1 Group 2
34.86 64.14 mean
21.99 20.46 standard deviation
7 7 n
Solution :
a). The IV or independent variable = Group 1
The DV or the dependent variable = Group 2
b).


Therefore, 

t = -2.579143
Now, 
df = 7 - 1
= 6
Therefore the value of p :

= 0.020908803
The p value is 0.0209

So we reject the null hypothesis and conclude that 
If you were to use the substitution method to solve the following system, we need to write one of the equation to an <span>expression equivalent to y. Let us say the second equation, we write it as follows:
</span><span>6x – 3y = –3
-3y = -6x - 3
y = 2x + 1
We substitute the equation to the first given equation as follows:
</span><span>2x – 5y = –3
</span>2x – 5(2x + 1) = –3
2x - 10x - 5 = -3
-8x = 2
x = -1/4
y = 2(-1/4) + 1 = 1/2
Answer:
I think it is the first number line
Step-by-step explanation:
I think it is this one because it is the only one that shows the placement of -1 and -5. I am sorry if the answer is wrong.
Answer:
Step-by-step explanation:

