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3 years ago

Angle θ is in standard position. If tanθ < 0 and cosθ = -4/5 , find sinθ.

1 answer:

8 0

Use the formula,
sin^2 x + cos^2 x =1

sin^2 x + (-4/5)^2 = 1
sin^2 x + 16/25 = 1

sin^2 x = 1-16/25

sin^2 x = (25-16)/25
sin^2 x = 9/25
sin x = +3/5 or -3/5

since both tan and cos are negative, sine will be positive (Quadrant 2).

sin x = 3/5.

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2 years ago

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$(x+2)^2 + (y-3)^2 = 10$

Step-by-step explanation:

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______________________________________________________

Given

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Plugging in this value of center in standard equation for circle given above we have

$(x-a)^2 + (y-b)^2 = r^2 \ substitute (a,b) \ with (-2,3) \\=>(x-(-2))^2 + (y-3)^2 = r^2 \\=>(x+2)^2 + (y-3)^2 = r^2 (1)$

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3 years ago

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