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icang [17]
3 years ago
5

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

t to y from the second equation is substituted into the first equation.
2x – 5y = –3
6x – 3y = –3 ...?
Mathematics
1 answer:
stellarik [79]3 years ago
4 0
If you were to use the substitution method to solve the following system, we need to write one of the equation to an <span>expression equivalent to y. Let us say the second equation, we write it as follows:

</span><span>6x – 3y = –3
-3y = -6x - 3
y = 2x + 1

We substitute the equation to the first given equation as follows:

</span><span>2x – 5y = –3
</span>2x – 5(2x + 1) = –3
2x - 10x - 5 = -3
-8x = 2
x = -1/4
y
= 2(-1/4) + 1 = 1/2
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What vaule of x makes th question true? 3x+2(x-5)=50 a. 8 b.9 c.11 d.12
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Hey Tierra7l, 

Lets solve your equation together step by step. 

3x+2\left(x-5\right)=50 

\mathrm{Expand}\:2\left(x-5\right):\quad 2x-10 

\mathrm{Distribute\:parentheses\:using}:\quad \:a\left(b+c\right)=ab+ac 

                                    a=2,\:b=x,\:c=-5 

2\cdot \:x+2\left(-5\right) 

\mathrm{Apply\:minus-plus\:rules} 

\:\:+\left(-a\right)=-a 

2x-2\cdot \:5 

\mathrm{Multiply\:the\:numbers:}\:2\cdot \:5=10 

2x-10 

3x+2x-10=50 

\mathrm{Add\:similar\:elements:}\:3x+2x=5x 

5x-10=50 

\mathrm{Add\:}10\mathrm{\:to\:both\:sides} 

5x-10+10=50+10 

\mathrm{Simplify} 

5x=60 

\mathrm{Divide\:both\:sides\:by\:}5 

\dfrac{5x}{5}=\dfrac{60}{5} 

\mathrm{Simplify} 

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Hope this helps, 

      AnthrαX <span>  </span>
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Sketch the domain D bounded by y = x^2, y = (1/2)x^2, and y=6x. Use a change of variables with the map x = uv, y = u^2 (for u ?
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Under the given transformation, the Jacobian and its determinant are

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