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4 years ago

Quadrilateral A has side lengths 2, 3, 5, and 6. Quadrilateral B has side lengths 4, 5, 8,

Mathematics

1 answer:

Dahasolnce [82]4 years ago

6 0

Answer:

No.

Step-by-step explanation:

2, 3, 5, 6

4, 5, 8, 10

If all of the sides are scaled, that must mean it is possible to maintain a ratio of each side.

2/4 = 0.5

3/5 = 0.6

5/8 = ?

6/10 = 0.6

No.

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Can u help me on this?

a_sh-v [17]

Answer:

Step-by-step explanation:

70-20=50

i don't sure correct or not

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3 years ago

Six sprinters are racing in a 100-meter dash. How many different ways can a gold, silver, and

horrorfan [7]

Answer:

Step-by-step explanation:

Explanation

6 sprinters are in a race. Any one of the 6 could win. None of them can win 2 medals. So the first result is 6

5 runners remain. The second medal goes to any one of the 5

4 runners remain after 1 of the 5 have been choosen. Any one of the 4 could win.

Answer 6 * 5 * 4 = 120

There are 120 ways of awarding 3 medals to 6 people.

3 0

2 years ago

If 6 spring roll serve 3 people how many people will 1 roll serve

Pavlova-9 [17]

Answer:

1/2 person

Step-by-step explanation:

We can use a ratio to solve

6 rolls 1 roll

------------ = -------------

3 people x people

Using cross products

6x =3

Divide each side by 6

6x/6 = 3/6

x = 1/2

1 roll will solve 1/2 person

7 0

3 years ago

The equation a=1/2(b^1+b^2)h can be determined the area, a, of a trapezoid with height, h, and base lengths, b^1 and b^2 Which a

Evgesh-ka [11]

The complete question is as follows.

The equation a = $\frac{1}{2}(b_1 + b_2 )h$ can be used to determine the area , a, of a trapezoid with height , h, and base lengths, $b_1$ and $b_2$ . Which are equivalent equations?

(a) $\frac{2a}{h} - b_2 = b_1$

(b) $\frac{a}{2h} - b_2 = b_1$

(d) $\frac{2a}{b_1 + b_2} = h$

(e) $\frac{a}{2(b_1 + b_2)}$ = h

Answer: (a) $\frac{2a}{h} - b_2 = b_1$ ; (d) $\frac{2a}{b_1 + b_2} = h$ ;

Step-by-step explanation: To determine $b_1$ :

a = $\frac{1}{2}(b_1 + b_2 )h$

2a = ( $b_1 + b_2$ )h

$\frac{2a}{h} = b_1 + b_2$

$\frac{2a}{h} - b_2 = b_1$

To determine h:

a = $\frac{1}{2}(b_1 + b_2 )h$

2a = $(b_1 + b_2)h$

$\frac{2a}{(b_1 + b_2)}$ = h

To determine $b_2$

a = $\frac{1}{2}(b_1 + b_2 )h$

2a = $(b_1 + b_2)h$

$\frac{2a}{h} = (b_1 + b_2)$

$\frac{2a}{h} - b_1 = b_2$

Checking the alternatives, you have that $\frac{2a}{h} - b_2 = b_1$ and $\frac{2a}{(b_1 + b_2)}$ = h, so alternatives A and D are correct.

4 0

3 years ago

What is the equation of the following line? be sure to scroll down first to see all answer options

andreyandreev [35.5K]

Answer:

The equation for the following graph:

$y = -\frac{1}{5}x$

Step-by-step explanation:

- You first need to find the slope by using the slope formula:

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

(where $(x_{1},y_{1})$ is the first point and $(x_{2}, y_{2})$ is the second point)

-Use the given points $(0,0)$ and $(10, -2)$ from the graph for the formula:

$m = \frac{-2 - 0}{10 - 0}$

Then, you solve:

$m = \frac{-2 - 0}{10 - 0}$

$m = -\frac{1}{5}$

After you have found the slope, use the slope $-\frac{1}{5}$ and the first point $(0,0)$ for the point-slope formula:

$y - y_{1} = m ( x - x_{1})$

(where $m$ is the slope and $(x_{1}, y_{1})$ is the first point)

$y - 0 = -\frac{1}{5} ( x - 0)$

Then, you solve:

$y - 0 = -\frac{1}{5} ( x - 0)$

$y - 0 = -\frac{1}{5}x - 0$

$y - 0 + 0 = -\frac{1}{5} - 0 + 0$

$y = -\frac{1}{5}x$

So, the equation for the following graph is $y = -\frac{1}{5}x$ .

7 0

3 years ago